Round the answer to the nearest hundredth.

Estimating the quotient 57.8 divided 81

rodikova [14]

It would be.703 i think hope this helps

5 0

2 years ago

How do I answer this question pls help me

n200080 [17]

Answer:

14.7 quarts

Step-by-step explanation:

Use the given equivalence figures to write a proportion. Solve the proportion for the unknown value.

__

quarts/liters = x/14 = 1/0.95 . . . . . the conversion is given as 1 qt = 0.95 L

Multiply by 14 to find x.

x = 14(1/0.95) ≈ 14.7

There are about 14.7 quarts in 14 liters.

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Additional comment

You are given a value in liters (14 liters) and asked for the equivalent in quarts. That means you want to change the units from liters to quarts. To do that, you can multiply the given value (14 liters) by a conversion factor that has quarts in the numerator and liters in the denominator. That is what the fraction 1/0.95 is in the above. You will note that units of liters cancel in this equation.

$(14\text{ liters})\times\dfrac{1\text{ quart}}{0.95\text{ liter}}=\dfrac{14}{0.95}\text{ quarts}\approx14.7\text{ quarts}$

This rule, "use a conversion factor that divides by the units you don't want and multiplies by the units you do want" applies to any units conversion problem. The conversion factor you use should always have equal quantities in the numerator and denominator. (Here, the equal quantities are 1 quart and 0.95 liters.)

You will notice that we treat units just like any variable. They can be multiplied, divided, cancelled, raised to a power. Only terms with like units can be added or subtracted.

4 0

2 years ago

How to find variables of these #2 & #3

Lubov Fominskaja [6]

So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles like $\bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}$

now.. for 3) will be the second picture below

$\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}$

8 0

3 years ago

In the game of roulette, a player can place a $5 bet on the number 3 and have a startfraction 1 over 38 endfraction probabilit

Misha Larkins [42]

The expected value per game is -0.26. Over 1000 games, you can expect to lose $263.16.

To find the expected value, we multiply the probability of winning by the amount of winnings, the probability of losing by the amount of loss, and adding those together.

We have a 1/38 chance of winning; 1/38(175) = $4.61. We also have a 37/38 chance of losing; 37/38(5) = $4.87.

$4.61-$4.87 = -$0.26 (rounded)

To five decimal places, our answer is -0.26136; multiplied by 1000 games, this is $261.36 lost.

3 0

3 years ago

Help! Please Which one

vodomira [7]

Answer:

cosine

Step-by-step explanation:

4 0

2 years ago