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12345 [234]
3 years ago
14

Differentiate between respiration and combustion

Chemistry
1 answer:
xxMikexx [17]3 years ago
7 0

Answer:

Both combustion and respiration involve the burning of the substrate. In both of these processes, the substance undergoes oxidation (in presence of oxygen).

...

Difference Between Respiration and Combustion.

Respiration Combustion

It takes place in a controlled manner inside the cells. It is an uncontrollable process.

Explanation:

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Covalent bond   a chemical bond formed by two electrons that are shared between two atoms
ionic bond<span>    a chemical bond formed by the electrostatic attraction between ions</span>
metallic bond<span>    a bond characteristic of metals in which mobile valence electrons are shared among positive nuclei in the metallic crystal</span>
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3 years ago
Read 2 more answers
Identify the item that does not have kinetic energy.
d1i1m1o1n [39]

Answer:

D

Explanation:

there is no other answer choice that does not move. This is a fool-proof question because all the other answer choices contain movement except the butterfly resting

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3 years ago
The rate of a certain reaction is given by the following rate law: rate Use this information to answer the question below. At a
AleksAgata [21]

Answer:

Initial rate of the reaction when concentration of hydrogen gas is doubled will be 3.2\times 10^6 M/s.

Explanation:

N_2+3H_2\rightarrow 2NH_3

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Initial rate of the reaction = R = 4.0\times 10^5 M/s

R = k\times [N_2][H_2]^3

4.0\times 10^5 M/s=k\times [N_2][H_2]^3

The initial rate of the reaction when concentration of hydrogen gas is doubled : R'

[H_2]'=2[H_2]

R'=k\times [N_2][H_2]'^3=k\times [N_2][2H_2]^3

R'=8\times k\times [N_2][H_2]^3

R'=8\times R=8\times 4\times 10^5 M/s=3.2\times 10^6 M/s

Initial rate of the reaction when concentration of hydrogen gas is doubled will be 3.2\times 10^6 M/s.

7 0
4 years ago
Use the following scenario to answer the question: A cell has an antiport protein on its apical surface. The cell is placed in a
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The correct answer is "Secondary active transport".

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Secondary active transport is a form of across the membrane transport that involves a transporter protein catalyzing the movement of an ion down its electrochemical gradient to allow the movement of another molecule or ion uphill to its concentration/electrochemical gradient. In this example, the transporter protein (antiporter), move 3 Na⁺ into the cell in exchange for one Ca⁺⁺ leaving the cell. The 3 Na⁺ are the ions moved down its electrochemical gradient and the one Ca⁺⁺ is the ion moved uphill its electrochemical gradient, because Na+ and Ca⁺⁺are more concentrated in the solution than inside the cell. Therefore, this scenario is an example of secondary active transport.

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3 years ago
What is acid according to arhenias concept?
nignag [31]

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Acid are those substances which release H + ions when dissolved in water.

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