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3 years ago

What effect does supercritical mass have on a nuclear reaction?

Chemistry

2 answers:

Firdavs [7]3 years ago

5 0

The reaction produces fewer neutrons its <span>rate increases and it produces less energy.</span>

Mama L [17]3 years ago

5 0

Answer:

The reaction rate increases.

Explanation:

To sustain a nuclear reaction, the mass of the reactor fuel should be theshold or sufficient for the reaction to carry. Critical mass is defined as the minimum quantity of the fissile material required to achieve a self-sustaining fission chain reaction under stated conditions. A critical mass is required in order to continue the chain reaction and the release of atomic energy.

Supercritical mass is the mass of reactor fuel which is more than needed to sustain the chain reaction. So when the state of supercritical mass is achieved, the nuclear rate increases exponentially.

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Which element when combined with fluorine would form a ionic compound

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3 years ago

The rate at which a certain Australian tree cricket chirps is 194/min at 28°C, but only 47.6/min at 5°C, From these data calcula

uysha [10]

Answer: The energy of activation for the chirping process is 283.911 kJ/mol

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

The expression used with catalyst and without catalyst is,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_2$ = rate of reaction at $28^0C$ = 194/min

$K_1$ = rate of reaction at $5^0C$ = 47.6 /min

$Ea$ = activation energy

R = gas constant = 8.314 J/Kmol

tex]T_1[/tex] = initial temperature = $5^oC=273+5=278K$

tex]T_1[/tex] = final temperature = $28^oC=273+28=301K$

Now put all the given values in this formula, we get

$\frac{194}{47.6}=\frac{E_a}{2.303\times 8.314}[\frac{1}{278}-\frac{1}{301}]$

${E_a}=283911J/mol=283.911kJ/mol$

Thus the energy of activation for the chirping process is 283.911 kJ/mol

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3 years ago

How are amplitude modulation and frequency modulation techniques similar?

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Answer:

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3 years ago

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Answer:

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3 years ago

4. How many moles are in 9.12 x 1023 molecules of sugar? And I want the steps to so that I can understand better

Aleksandr-060686 [28]

Answer:

Step 1: List the known quantities and plan the problem.

Known

number of C atoms = 4.72 × 10 24

1 mole = 6.02 × 10 23 atoms

Unknown

4.72 × 10 24 = ? mol C

One conversion factor will allow us to convert from the number of C atoms to moles of C atoms.

Step 2: Calculate.

4.72 times 10^{24} text{atoms C} times frac{1 text{mol C}}{6.02 times 10^{23} text{atoms C}}=7.84 text{mol C}

Step 3: Think about your result.

The given number of carbon atoms was greater than Avogadro’s number, so the number of moles of C atoms is greater than 1 mole. Since Avogadro’s number is a measured quantity with three significant figures, the result of the calculation is rounded to three significant figures.

Explanation:

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3 years ago