sodium chloride
and lead (II) acetate
potassium sulfate and strontium iodide
chromium (III) nitrate and sodium phosphate
1.
2NaCl + Pb(CH3COO)2 → 2NaCH3COO + PbCl2
2.
K2SO4 + SrI2 → KI + SrSO4
3.
Cr(NO3)3 + Na3PO4 →CrPO4 + NaNO3
When the magnitude of the charge Q = I*T
when we have I current = 2.3
and T = 35 min * 60 = 2100 s
by substitution:
∴ Q = 2.3 * 2100
= 4830 C
according to this reaction equation:
Cu2+ + 2e- → Cu
we can see that 1 mol Cu2+ need 2 mol e- to produce Cu
mol of electron e- = Q / faraday's constant
= 4830 / 96485
= 0.05 mol
when 1 mol Cu2+ → 2 mol e-
?? ← 0.05 mol
∴ moles Cu2+ = 0.05 /2 = 0.025 mol
∴ mass Cu2+ = moles Cu2+ * molar mass Cu2+
= 0.025 * 64
= 1.6 g
The solution for this problem is:
Let x = speed of wind
Speed of plane with the wind = x + 100
Speed of plane against the wind = 100 -x
We will be using the formula for distance which is (Rate)(Time), getting the formula for time would be distance/rate Time to travel 600 miles with the wind = Time to travel 400 miles against the wind 600/(x + 100) = 400/(100 - x)
400(x + 100) = 600(100 - x)
400x + 40000 = 60000 - 600x
1000x = 20000
x = 20000/1000
x = 20 mph
