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Explanation:
Given parameters:
Mass of Br-79 = 78.918 amu
Abundance = 50.69%
Unknown:
Mass of Br - 81 = ?
Solution:
Relative Atomic mass of Br = 80
The proportion by which each fraction of an isotope occurs in nature is called the geonormal abundance.
RAM = Ma Ba + McBc
The formula above is used to find the average mass of the given isotopes.
Since we know the percentage abundance of Br-79, that of Br-81 = 100-50.69= 49.31%
RAM = Ma Ba + McBc
RAM = relative atomic mass
Ma Ba = mass and abundance of Br-79
McBc = mass and abundance of Br-81
80 = (78.918 x ) + (
x C)
80 = 40 + 0.49C
0.49C = 40
C = = 81.63amu
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