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3 years ago

A group of friends wants to go to the amusement park. They have no more

Mathematics

2 answers:

dusya [7]3 years ago

7 0

Answer:

Inequality: 11x+16.5\le11011x+16.5≤110

Answer: x \le 8.5x≤8.5

Step-by-step explanation:

NeX [460]3 years ago

6 0

Answer:

110-16.50=93.50

93.50÷11= 8.5

answer is 8 people

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Evaluate the expression for the given value of the variables.

zzz [600]

For every c substitute 4 and for every d substitute -2

c=4
d=-2

6c + 5d - 4c - 3d + 3c - 6d

= 6(4)+ 5(-2)- 4(4)- 3(-2)+ 3(4)- 6(-2)

=24+(-10)-16-(-6)+12-(-12)

=24-10-16+6+12+12

=28

7 0

3 years ago

Find the next two terms in this<br> sequence.<br> 1, -3, 9, -27, 81, [?],

fiasKO [112]

-243

Step-by-step explanation:

số dương nhân -3 thì đc số âm, số âm nhân với -3 để đc số dương.

vd: 1. -3 = -3 ; -3 .-3= 9 ;..... 81 . -3= -243

7 0

2 years ago

Read 2 more answers

An ore ship is traveling west toward Duluth on Lake Superior at 18 miles per hour. The bearing of Split Rock Lighthouse is 285de

goblinko [34]

We are given
v = 18 m/hr west
θ1 = 285°
θ2 = 340°

After 1 hours, the distance traveled by the ship is
dv = 18 mi

The distance between the ship and the lighthouse is
d = 18 / cos 340
Solve for d<span />

5 0

3 years ago

Derivative of cos(4x)

son4ous [18]

D/dx ( cos (4x)) = - sin (4x) · d/dx ( 4x) = - 4 sin (4x)

7 0

3 years ago

Mason walked on Monday, Wensday, and Friday. Use these clues to find how far he walked each day. These distances were six-eights

krok68 [10]

Answer:

Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

Step-by-step explanation:

Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.

distances are $\frac{6}{8}, \frac{1}{4}, \frac{1}{6}$ that are 0.75, 0.25 and 0.17 respectively.

Now, he didn't walk farthest on Monday and also walked less on Friday than Monday.

∴ Less distance travelled is $\frac{1}{6}$ which is on friday and then $\frac{1}{4}$ on monday.

Rest distance which is $\frac{6}{8}$ on wednesday.

Hence, Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

4 0

3 years ago

Read 2 more answers