3 years ago

The zeros of the functions f(x) = 3x^2 - 3x - 6

Mathematics

1 answer:

Butoxors [25]3 years ago

7 0

The answer is: x = 2 ∨ x = -1

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Given the functions f(x) = x2 + 6x − 1, g(x) = –x2 + 2, and h(x) = 2x2 − 4x + 3, rank them from least to greatest based on their

kotegsom [21]

You can find an axis of symmmetry of quadratic function by using this formula:

$x=-\dfrac{b}{2a} \\ \\ \hbox{Where function is} \ \ f(x)=ax^2+bx+c \ \ \hbox{assuming} \ \ a\neq 0$

An axis of f(x):

$x=-\dfrac{6}{2 \cdot 1}=-\dfrac{6}{2}=-3$

Of g(x):

$x=-\dfrac{0}{2 \cdot (-1)}=\dfrac{0}{2}=0$

Of h(x):

$x=-\dfrac{-4}{2 \cdot 2}=\dfrac{4}{4}=1$

At least to greatest you've got -3, 0, 1 so f(x), g(x), h(x). Answer a

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3 years ago

What is Q1 AND Q3 AND IQR OF THE NUMBERS<br>2,12,52,33,8,14

Sedaia [141]

It is 25.

Q1 is 8
Q3 is 33

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3 years ago

Read 2 more answers

What is the equation of a line that passes through the point (2, 7) and is perpendicular to the line whose equation is y=x4+5 ?

Valentin [98]

Attached a solution and showed work.