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ioda
3 years ago
11

What is 1.147 , 1.15 , 1.098 , 0.884 from greatest to least

Mathematics
2 answers:
SOVA2 [1]3 years ago
5 0
1.15,1.147,1.098,.884
HACTEHA [7]3 years ago
3 0
1.15, 1.147, 1.098, 0.884
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Consider circle C with angle ACB measuring 3
deff fn [24]

Answer:

Radius of circle C= 3in

Step-by-step explanation:

We are given that a circle C .

Measure of an angle ACB=\theta=3 radians

Measure of minor arc=9 in

We have to find the radius of circle C.

We know that

\theta=\frac{l}{r}

Where \theta in radians

Substitute the value in the given formula

3=\frac{9}{r}

r=\frac{9}{3}=3 in

Hence, the radius of circle C=3 in

But, options do not match with this answer.

3 0
4 years ago
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Someone help me on this
Advocard [28]

Answer:

idk

Step-by-step explanation:

8 0
3 years ago
How many 1/2 can go into 1395
kirill115 [55]

Answer:

2790

Step-by-step explanation:

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4 0
3 years ago
1) Is y=-3 a solution to the equation-3x^2=-27
sergey [27]

Answer:

1)Yes

2)No

Step-by-step explanation:

1) 3x^2 = -27

3 (-3)^2 = -27

Once you substitute your value in for x, you can follow the rule <u>PEMDAS</u> to solve the equation.

3 (-9) = -27

-27 =-27

2) 10 - 5x = y

In an ordered pair, the first number is x and the second number is y.

10 - 5 (-4) = 10

10 - 20 = 10

-10 = 10

-10 ≠ 10

PEMDAS: A rule that states solving an equation by the order of operations:

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

8 0
3 years ago
Find the cube roots of 27(cos 279° + i sin 279°).
UNO [17]

The solution would be like this for this specific problem:

<span>27(cos 279° + i sin 279°).
</span><span>(cosx +i sinx) = cox(nx)) + i sin(nx)
</span><span>(27×(cos 279+i sin 279)<span>)1/3</span>=<span>27 1/3</span>×(cos 279+i sin 279<span>)<span>1/3
</span></span></span><span><span>2713</span>=<span>27−−√3</span>=?
</span><span>3×(cos279+i sin279<span>)<span>1/3
</span></span></span><span>3×(cos 279+i sin 279<span>)13</span>=3(cos 279/3+i sin 279/3)

</span><span>279/3 = 93
cube root = </span>3(cos 93 + i sin 93)

<span>I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>

7 0
4 years ago
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