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3 years ago

What is 1.147 , 1.15 , 1.098 , 0.884 from greatest to least

Mathematics

2 answers:

SOVA2 [1]3 years ago

5 0

1.15,1.147,1.098,.884

HACTEHA [7]3 years ago

3 0

1.15, 1.147, 1.098, 0.884

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Nancy walked 516 yards in 6 minutes and then another 368 yards in 4 minutes. What was Nancy's average speed? * A. 89 yd/min B. 8

Rina8888 [55]

Average speed = (total distance covered) / (time to cover the whole distance)

Total distance = (516 + 368) = 884 yards
Total time = (6 + 4) = 10 minutes

Average speed = (884 yards) / (10 minutes)

Average speed = 88.4 yards/minute (C)

Other ways to write the same speed:

-- 4.42 feet/second
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-- 53.04 inches/second
-- 5,304 yards/hour
-- 3.014 mph (rounded)
-- 810.07 furlong/fortnight

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3 years ago

27^{3x}=(1/9)^x<br> write in b^x=b^y form

iogann1982 [59]

Answer:

3^9x=3^-2x

Step-by-step explanation:

27^3x=(1/9)^x

3^3×3x=(1/3^2)^x

3^9x=3^-2x

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3 years ago

Factor 9x6 – 16 y completely.

sveticcg [70]

Answer:

(3x^3 - 4y^3) ( 3x^3 + 4y^3)

Step-by-step explanation:

9x^6 – 16 y^6

Rewriting as

(3x^3) ^2 - ( 4y^3) ^2

This is the difference of squares a^2 - b^2 = (a-b)(a+b)

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3 years ago

If an angle of 96 degrees is rotated 90 degrees clockwise. what the measure?

Natali [406]

Answer:

The measure is 6°.

Step-by-step explanation:

If an angle of 96 degrees is rotated 90 degrees clockwise then the measure of the new angle will be given by

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3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$