In electrical circuit, this arrangement is called a R-L series circuit. It is a circuit containing elements of an inductor (L) and a resistor (R). Inductance is expressed in units of Henry while resistance is expressed in units of ohms. The relationship between these values is called the impedance, denoted as Z. Its equation is
Z = √(R^2 + L^2)
Z = √((1.24×10^3 ohms)^2 + (6.95×10^-6 H)^2)
Z = 1,240 ohms
The unit for impedance is also ohms. Since the circuit is in series, the voltage across the inductor and the resistor are additive which is equal to 12 V. Knowing the impedance and the voltage, we can determine the maximum current.
I = V/Z=12/1,240 = 9.68 mA
But since we only want to reach 73.6% of its value, I = 9.68*0.736 = 7.12 mA. Then, the equation for R-L circuits is

, where τ = L/R = 6.95×10^-6/1.24×10^3 = 5.6 x 10^-9
Then,
t = 7.45 nanosecondsPart B.) If t = 1.00τ, then t/τ = 1. Therefore,
I = 6.12 mA
Answer: The power is a measure of the rate at which work is done (or similarly, at which energy is transferred). The standard unit of power is Watt (1W). The power is determined by the change in energy, delta E (number of joules) and delta t, which is the time taken in seconds then: P= delta E/ delta t.
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Explanation:
Will this one work?...................
The charge on the droplet must be 
Explanation:
In order for the oil droplet to be in equilibrium, the force of gravity acting on it (the weight, acting downward) must be equal to the electrical force acting upward.
The gravitational force is:

which is equivalent to the weight of the droplet.
The electric force is given by:

where
q is the charge on the oil droplet
is the magnitude of the electric field
Since the two forces must be equal,

And solving for q,

Learn more about gravitational force and electric force:
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Explanation:
Given that the first ball is thrown vertically and upward.
since it reaches the throwers hand after 3 seconds, then the time taken to reach maximum height is
= T/2
=3/2
=1.5 seconds
Also, the projection angle for the second ball is 30°
we know that at maximum height vertical velocity is 0
therefore the final velocity of the first ball is
Vy= 0
Also, since the first ball is thrown upward the horizontal velocity is 0
Vx=0
from the first law of motion
Vy=u+at
Vy=0, a= -g
Uy=gt
Uy=9.81*1.5
Uy=14.7m/s
since both reach the same height, they will have the same vertical velocity
Uy= Vo sin∅
Vo=Uy/sin∅
Vo= 14.7/sin 30
Vo=29.4m/s