Let say the two train cars are of masses
and 
now if the speed of two cars are
and 
then we can say that the momentum of two cars before they collide is given by

here two cars are moving in opposite direction so we can say that the net momentum is subtraction of two cars momentum.
Now since in these two car motion there is no external force on them while they collide
So the momentum of two cars are always conserved.
hence we can say that the final momentum of two cars will be same after collision as it is before collision

Answer:
Zero
Explanation:
W = F × s
F = 10 N,
t = 3min = 180sec
s = 0( no change in postion)
W = 10 ×0
W = 0
Answer:
0.66
Explanation:
By using the formula
u = v^2 / r g
Where u is coefficent of friction
u = 23.5 × 23.5 / (85 × 9.8)
u = 0.66
Answer:
896 kJ
Explanation:
KInetic Energy = 1/2 m v^2
= 1/2 (1120)(40^2) = 896 000 J or 896 kJ
I see the word "when..." kind of fading out at the end of the first line.
Whatever comes after it may be important.
If you're just supposed to copy the expression into the box,
then the problem is that you left the 'e' out of it.
I'm guessing that you're supposed to enter whatever the expression becomes
when either N₀ or ' t ' has some special value that's in the first line.
Just taking a wild guess here . . . . .
If it's "Enter the expression ..... , when t=0 ." ,
then the correct answer in the box is N₀ .
But that's just a wild guess. As I pointed out, you cut off
the picture in the middle of the word 'when', and I've got
a hunch that there's something important after it.