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Ksenya-84 [330]
3 years ago
14

Many household products we consider necessary today such as AM and FM radios, televisions, wireless networks, cordless and cellu

lar telephones, remote-controlled toys, and GPS receivers use ____ to transmit information to humans all over the world.
Physics
2 answers:
satela [25.4K]3 years ago
6 0
They use what is in physics called "Radio waves" ;)
san4es73 [151]3 years ago
4 0
I want to say frequencies would be the answer. I could be wrong though. Hope this may have helped!
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consumers get energy from eating other things plant from sun

Explanation:

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Que es la friccion <br> Cual es la primera ley de newton
lidiya [134]

Answer:

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5 0
3 years ago
(a) What is the minimum width of a single slit (in multiples of λ ) that will produce a first minimum for a wavelength λ ? (b) W
Kitty [74]

Answer:

The minimum value of width for first minima is λ

The  minimum value of width for 50 minima is 50λ

The  minimum value of width for 1000 minima is 1000λ

Explanation:

Given that,

Wavelength = λ

For D to be small,

We need to calculate the minimum width

Using formula of minimum width

D\sin\theta=n\lambda

D=\dfrac{n\lambda}{\sin\theta}

Where, D = width of slit

\lambda = wavelength

Put the value into the formula

D=\dfrac{n\lambda}{\sin\theta}

Here, \sin\theta should be maximum.

So. maximum value of \sin\theta is 1

Put the value into the formula

D=\dfrac{1\times\lambda}{1}

D=\lambda

(b). If the minimum number  is 50

Then, the width is

D=\dfrac{50\times\lambda}{1}

D=50\lambda

(c). If the minimum number  is 1000

Then, the width is

D=\dfrac{1000\times\lambda}{1}

D=1000\lambda

Hence, The minimum value of width for first minima is λ

The  minimum value of width for 50 minima is 50λ

The  minimum value of width for 1000 minima is 1000λ

4 0
3 years ago
A devout halloweener not only dressed as an astronaut, but travelled to the moon for the full experience. The astronaut jumps on
nikdorinn [45]

Answer:

2.78 m

Explanation:

At the peak, the velocity is 0.

Given:

a = -1.6 m/s²

v₀ = 2.98 m/s

v = 0 m/s

x₀ = 0 m

Find:

x

v² = v₀² + 2a(x - x₀)

(0 m/s)² = (2.98 m/s)² + 2(-1.6 m/s²) (x - 0 m)

x = 2.775 m

Rounded to 3 sig-figs, the astronaut halloweener reaches a maximum height of 2.78 meters.

5 0
3 years ago
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