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Physics

1 answer:

Viefleur [7K]3 years ago

8 0

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A ball is kicked horizontally from a 60 meter tall cliff at 10 m/s. How far from

o-na [289]

Hi there!

We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.

$\large\boxed{\Delta d = v_it+ \frac{1}{2}at^2}}$

There is NO initial vertical velocity, so:

$\large\boxed{\Delta d= \frac{1}{2}at^2}}$

Rearrange to solve for time:

$2\Delta d = at^2\\\\t = \sqrt{\frac{2\Delta d}{g}}$

Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)

$t = \sqrt{\frac{2(60)}{(9.8)}} = 3.5 s$

Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:

$\large\boxed{d_x = vt}\\\\d_x = 10(3.5) = \karge\boxed{35 m}$

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In graphing enthalpy entropy and state changes which two variables are included ? A. volume and temperature B. amount of heat ad

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In graphing enthalpy entropy and state changes the two variables that are included are amount of heat added and pressure. The answer is letter D. The rest of the choices do not answer the question above.

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4 years ago

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If v =5.00 meters/second and makes an angle of 60 with the negative direction of the y-axis coalculate the possible values of vx

Sever21 [200]

An angle of 60 degrees with the negative y-axis could mean 60 degrees clockwise or counterclockwise, which translates to two possible angles (starting from the positive x-axis and moving counterclockwise) of 210 degrees or 330 degrees.

Then the horizontal component $v_x$ of a velocity vector $\mathbf v$ with magnitude $5.00\,\dfrac{\mathrm m}{\mathrm s}$ could be one of two expressions: