What is another name for the heat-trapping gases

Which statement is true if the refractive index of medium A is greater than that of medium B?

allsm [11]

Answer:

I think it is C

Explanation:

7 0

3 years ago

For a certain optical medium the speed of light varies from a low value of 1.90 × 10 8 m/s for violet light to a high value of 2

Dmitry_Shevchenko [17]

Answer:

a. The refractive index ranges from 1.5 - 1.56

b. 18.7° for violet light and 19.5° for red light.

c. 33.7° for violet light and 35.3° for red light.

Explanation:

a. The refractive index of an object is the ratio of the speed of light in a vacuum and the speed of light in the object.

Mathematically,

$n = \frac{c}{v}$

The speed of violet light in the object is $1.9 * 10^8 m/s$ .

The speed of red light in the object is $2 * 10^8 m/s$

Hence, the refractive index for violet light is:

$n = \frac{3 * 10^8 }{1.9 * 10^8} \\\\n = 1.56$

and for red light, it is:

$n = \frac{3 * 10^8 }{2 * 10^8} \\\\n = 1.5$

Hence, the refractive index ranges from 1.5 - 1.56.

b. The refractive index is also the ratio of the sine of the angle of incidence to the sine of the angle of refraction.

$n = \frac{sin(i)}{sin(r)}$

The angle of incidence is 30°.

The angle of refraction for violet light will be:

$1.56 = \frac{sin(30)}{sin(r)}\\ \\sin(r) = \frac{sin(30)}{1.56} = \frac{0.5}{1.56} \\\\sin(r) = 0.3205\\\\r = 18.7^o$

And the angle of refraction for red light will be:

$1.5 = \frac{sin(30)}{sin(r)}\\ \\sin(r) = \frac{sin(30)}{1.5} = \frac{0.5}{1.5} \\\\sin(r) = 0.3333\\\\r = 19.5^o$

The angle of refraction for red light is larger than that of violet light when the angle of incidence is 30°.

c. The angle of incidence is 60°.

The angle of refraction for violet light will be:

$1.56 = \frac{sin(60)}{sin(r)}\\ \\sin(r) = \frac{sin(60)}{1.56} = \frac{0.8660}{1.56} \\\\sin(r) = 0.5551\\\\r = 33.7^o$

And the angle of refraction for red light will be:

$1.5 = \frac{sin(60)}{sin(r)}\\ \\sin(r) = \frac{sin(60)}{1.5} = \frac{0.8660}{1.5} \\\\sin(r) = 0.5773\\\\r = 35.3^o$

The angle of refraction for red light is still larger than that of violet light when the angle of incidence is 60°.

6 0

3 years ago

What is an athlete’s momentum if the athlete has a velocity of 7.5 m/s and has a mass of 70kg?

Bezzdna [24]

Answer:

525 kg.m/s

Explanation:

★ Momentum = Mass× Velocity

→ P = (7.5 × 70) kg.m/s

→ P = (75 × 7) kg.m/s

→ P = 525 kg.m/s

8 0

2 years ago

Which of the following situations would cause the greatest decrease in the motion of molecules in a system

Yakvenalex [24]

At 0 Kelvin everything stops moving ( even electrons ), so you could try to decrease the system's temperature
0 Kelvin = -273 Celsius

3 0

3 years ago

Ayuda plisss, es urgente

kramer

(Lo siento si mi español es malo, no es mi primera lengua )

1. velocidad media = desplazamiento/tiempo

desplazamiento = 0 porque el athelete vuelve al punto inicial en un círculo

velocidad media = desplazamiento/tiempo = 0/10 = 0

2. la distancia entre A y B es 5 cm porque

a^2 + b^2 = c^2 (el teorema de Pitágoras) así:

rapidez media = distancia/tiempo = 5/5 = 1 cm/s o 0.01 m/s

y yo no se cómo hacer 3-5 :( lo siento

3. Creo que es dos triángulo s AB y CD menos la línea de fondo

5. Creo que es E + F porque B y D b y d cancelarse el uno al otro y C y C tambien pero no lo sé con seguridad.

8 0

2 years ago