Question

If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 55.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Answer 1

Answer:

14.79 kgm/s

Explanation:

Data provided in the question

Let us assume the mass of baseball =  m = 0.145 kg

The Initial velocity of pitched ball = $v_i$ = 47 m/s

Final velocity of batted ball in the opposite direction = $v_f$= -55m/s

Based on the above information, the change in momentum is

$\Delta P = m(v_f -v_i)$

$= 0.145 kg(-55m/s - 47m/s)$    

= 14.79 kgm/s

Hence, the magnitude of the change in momentum of the ball is 14.79 kg m/s