What is the horizontal asymptote of the function f (x)= x^2-25/2x^2 ?
1 answer:
You might be interested in
Remark
Study the triangle carefully. It may not be exactly as you have drawn it, but it will work if you just follow the givens.
Givens
AC = 2
AB = 1
BC = sqrt(3)
Step One
Find Cos C
Cos(C) = adjacent / Hypotenuse
Cos(C) = BC / AB
Cos(C) = sqrt(3)/2
Step Two
Find Sin(A)
Sin(A) = opposite / hypotenuse
Sin(A) = AB / AC
Sin(A) = 1/2
Step Three
Find Cos(C) * Sin(A)
Cos(C) * Sin(A) = sqrt(3)/2 * 1/2 = sqrt(3) / 4 <<<< Answer
