Answer: V≈ 394.57m³
Step-by-step explanation:
Complete Question
Although the first quarter of 2002 was quite dismal on Wall Street, mutual funds investing in gold companies rose an average of 35.2%. Assume that the distribution of returns in the first quarter of 2002 for mutual funds specializing in gold companies is fairly symmetrical with a mean of 35.2% and a standard deviation of 20%. If random samples of 16 gold stock funds were selected:
90% of the sample mean returns are between what two values symmetrically distributed around the mean?
Answer:
The two values symmetrically distributed around the mean are
21.87\% and 43.17\%
Step-by-step explanation:
From the question we are told that
The sample size is ![n = 16](https://tex.z-dn.net/?f=n%20%3D%2016)
The sample mean is ![\= x = 0.352](https://tex.z-dn.net/?f=%5C%3D%20x%20%20%3D%20%200.352)
The standard deviation is ![\sigma = 0.20](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%200.20)
Generally the degree of freedom is mathematically represented as
![df = n -1](https://tex.z-dn.net/?f=df%20%3D%20n%20-1)
=> ![df = 16 -1](https://tex.z-dn.net/?f=df%20%3D%2016%20-1)
=> ![df = 15](https://tex.z-dn.net/?f=df%20%3D%2015)
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the t distribution table the critical value of
at a degree of freedom of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 90% confidence interval is mathematically represented as
=>
converting to percentage
=>
Hence the 90% of the sample mean returns are between 21.87\% and 43.17\%
Answer: Student tickets sold= 1,035 Adult tickets sold= 400
Step-by-step explanation: S=1035 Number of student tickets
A+S=1435
A+1035=1435
A=1435-1035
A=400 Number of adult tickets
PROOF:
5*400+1035*1.50=3552.50
2000+1552.50= 3552.50
3552.50= 3552.50
Answer:
Use the straightedge to draw GK−→−. Place the point of the compass on point H and draw an arc in the interior of the angle. Label the intersection of the arcs in the interior of the angle as point K. Place the point of the compass on point G and draw an arc that intersects the sides of ∠G.
Answer is 26 bags
Step by step
First find the least common multiple (LCM) of the 3 nuts. First I checked to see if 26 was a multiple of 78 and 52, yes it is! 26 is the LCM.
26/26 = 1 almond per bag
52/26 = 2 peanuts per bag
78/26 = 3 pecans per bag.
So all 26 bags will contain 1 almond, 2 peanuts and 3 pecans.
Problem solved. Not a very big snack bag in my opinion.