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BigorU [14]
3 years ago
8

How many milliliters of a stock solution of 2.00M KNO3 would you need to prepare 150mL of a 0.3M solution?

Chemistry
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer:

The answer is "22.5"

Explanation:

Concentration:

M_1= 0.3 \ m \ of\ KNO_3\\\\M_2=2.00\ M\\\\  

Volume:

V_1=150 \ ml \ of\  KNO_3 \\\\V_2=?

Using formula:

M_1V_2=M_2V_2\\\\V_2=\frac{M_1V_1}{M_2}\\\\

    =\frac{0.3 \times 150}{2}\\\\=\frac{45}{2}\\\\=22.5

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