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Hoochie [10]
3 years ago
6

Mrs. Cashmore bought a large melon. She cut a piece that weighed 1 1/8 pounds and gave it to her neighbor. The remaining piece o

f melon weighed 6/8 pound. How much did the whole melon weigh? * in mixed number
Mathematics
1 answer:
lina2011 [118]3 years ago
7 0

Answer: 1⁷/₈ pounds

Step-by-step explanation:

The weight of the whole melon is the sum of the 1¹/₈ pounds given to the neighbor and the 6/8 pounds remaining.

Convert improper to proper:

1¹/₈  = 9/8

= 9/8 + 6/8

= 15/8

= 1⁷/₈ pounds

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Miki prepared two gallons of a beverage that contains tea and lemonade in the ratio tea:lemonade=3:1. If Miki then added one-hal
Advocard [28]

Ratio of tea to lemonade in the new mixture is 3 : 2

<h3><u>Solution:</u></h3>

Given that volume of a beverage prepared by Miki containing tea and lemonade = 2 gallons

Ratio of tea and lemonade in beverage prepared by Miki = 3:1  

Then Miki added one half of gallon of lemonade to the mixture.  

Need to determine ratio of tea and lemonade in the new mixture.

Lets first calculate volume of tea and volume of lemonade in old mixture that is the one before adding one half of gallon of lemonade.

Given ratio of tea and lemonade in old mixture = 3: 1 , means our of every four parts of mixture, 3 parts are of tea and 1 part is of lemonade.

=>\text { In old mixture, } \frac{3}{4} \text { is tea and } \frac{1}{4} \text { is lemonade. }

\text { Volume of tea in old mixture }=\frac{3}{4} \times \text { volume of old mixture }=\frac{3}{4} \times 2 \text { gallons }=1.5 \text { gallons }

\text { Volume of lemonade in old mixture }=\frac{1}{4} \times \text { volume of old mixture }=\frac{1}{4} \times 2 \text { gallons }=0.5 \text { gallons }

Given that one-half gallon of lemonade is added to old mixture to form new mixture.

So Volume of lemonade in new mixture = Volume of lemonade in old mixture + one half gallon = 0.5 + 0.5 = 1 gallon

As there is no change in volume of tea , so Volume of Tea in new mixture = Volume of tea in old mixture = 1.5 gallons

Ratio of tea : lemonade in new mixture = 1.5 : 1 = 3 : 2  

Hence ratio of tea to lemonade in the new mixture is 3 : 2.

7 0
3 years ago
Its pitcher is shaped like a cylinder with a radius of 1 centimeter and a height of 7.8 cm. What's this pitcher plant's approxim
nordsb [41]

Answer:

The pitcher plant's approximate volume is 24.492 \text{cm}^{3}.

Step-by-step explanation:

We are given that a  pitcher is shaped like a cylinder with a radius of 1 centimeter and a height of 7.8 cm.

Let the radius of a cylinder = r = 1 cm

and the height of a cylinder = h = 7.8 cm

As we know that the volume of a cylinder is given by;

The volume of a cylinder = \pi r^{2}h

                           = 3.14 \times 1^{2} \times 7.8  {taking approximate value of \pi to be 3.14}

                           = 3.14 \times 7.8

                           = 24.492 \text{cm}^{3}

Hence, this pitcher plant's approximate volume is 24.492 \text{cm}^{3}.

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Answer:

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