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suter [353]
3 years ago
13

Which quadratic function has a vertex point of (3,5) and passes through the point (-2,55)?

Mathematics
1 answer:
Alex17521 [72]3 years ago
8 0

9514 1404 393

Answer:

  f(x) = 2(x -3)² +5

Step-by-step explanation:

For vertex (h, k) and scale factor 'a', the vertex form is ...

  f(x) = a(x -h)² +k

We can fill in the values of h and k from your vertex, and use the values of the extra point to find 'a'.

  55 = a(-2 -3)² +5

  50 = 25a . . . . . . . . subtract 5

  a = 2 . . . . . . . . . . . divide by 25

So, the function is ...

  f(x) = 2(x -3)² +5

__

In standard form, that will be ...

  f(x) = 2x² -12x +23

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kirill115 [55]

I'll assume those are squares.  We know D is an identity:

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Dividing through by \sin ^2 x

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Step-by-step explanation:

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The width of a rectangle is 2x²+9x-7 and the length is x²-9. Find the perimeter of the rectangle.​
OLEGan [10]

Answer:

---

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6 0
3 years ago
20 POINTS!!!!!!!!
Irina18 [472]
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3 years ago
What is 4c + 8c = -55 + 3c
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To solve this, you need to isolate/get the variable "c" by itself in the equation:

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