Claire drew a house for her art class. The drawing is shown below.
1 answer:
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Answer:
- P(t) = 100·2.3^t
- 529 after 2 hours
- 441 per hour, rate of growth at 2 hours
- 5.5 hours to reach 10,000
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
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(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
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(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
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(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000
Answer:
Between 12.614 years and 16.386 years
Step-by-step explanation:
Given that:
Mean age (μ) = 14.5 years, standard deviation (σ) = 4.6 years, number o sample (n) and the confidence interval (c) = 90% = 0,9
α = 1 -c = 1 -0.9 = 0.1
The z score of is the same as the z score of 0.45 (0.5 - 0.05). This can be gotten from the probability distribution table. Therefore:
The margin of error (e) = =
The interval = μ ± e = 14.5 ± 1.886 = (12.614 ,16.386)
Answers:
a= 5x±
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6
u=±
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2
<h2>Brainliest please!!!! It took me a while to figure this out!</h2>