Answer:
1/2
Step-by-step explanation:
m=y2-y1/x2-x1
8-6=2
10-6=4
(2/4)/2=(1/2)
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Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer:
A.
In 4231, the value of the digit 3 is 110 less than the value of the digit 3 in 3421.
Step-by-step explanation:
We can see that the value of 3 In 4231 is in ten while the value of 3 in 3421 is in thousands.
So to get the actual division factor, let's take 3300 and divide it by 30,
3300/30 = 110
So it's clear already, that the value of 3 in 4231 is 110 times less to the value in 3421
(-9x²-2x) - (-9x²-3x) = (-9x²-2x) +(9x²+3x) = -9x²-2x+9x²+3x = (-9x²+9x²)+(-2x+3x) = x
Answer:

Step-by-step explanation:
= 2k - x
Given that k = 9, x = 5
= 2(9) - 5
= 18 - 5
= 13
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope his helped!
<h3>~AH1807</h3>