Answer:
2.5e-0.04x = 1.2 + 0.2x
Step-by-step explanation:
Given that:
Insect A:
Initial population, Po = 2.5 million
Rate of decline = 4%
Insect B:
Initial Population (Po) = 1.2 million
Yearly increase = 200,000 = (200,000/1,000,000) = 0.2
For insect A:
P(t) = Po(1 - r)^t = Po*e^-rt
Po*e^-rt = 2.5e^-0.04t ----(1)
For Insect B:
P(t) = Po + (yearly increase) * t
P(t) = 1.2 + 0.2t - - - - - (2)
Equating (1) and (2)
2.5e^-0.04t = 1.2 + 0.2t
We have that
<span>2cscx-3=-5---------> 2cscx=-5+3---------> cscx=-2/2---------> cscx=-1
we know that
csc x=1/sin x
then
1/sin x=-1--------------> sin x=-1
x=arcsin (-1)---------> x=-90</span>°
x=-90°---------------> 360°-90°-----------> x=270°------------> 3pi/2<span>
the answer is
x=3pi/2 radians
</span>
Answer:
3
lazy approach was with a graphic plotting program, but you can also calculate it. with the pq-formula.
p = -6
q = 9
x = -p/2 +- sqrt( (p/2)² - q)
x = -(-6)/2 +- sqrt ( (-6/2)² - 9)
x = 3 +- sqrt(9-9)
x = 3 +- sqrt(0)
x = 3 +- 0
x = 3
