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Daniel [21]
4 years ago
14

Gravitational force varies (changes) inversely with what?

Physics
1 answer:
butalik [34]4 years ago
5 0

Answer: square of distance ww

Explanation:

Newton law of universal gravitation state that the gravitational force of attraction between two masses is directly proportional to the product of the masses and inversely proportional to the Square of their distance apart

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A car hits a wall with a force of 80 N and
ASHA 777 [7]
Formula for acceleration: A=Force/Mass
A=F/M
A=80N/4.5kg
A=17.7 m/s^2

Unit for A is meters per second (m/s^2)
Hope this helps :)
5 0
3 years ago
What must a system owner do, once the threshold leak rate has been exceeded on any low-pressure system using an ozone-depleting
soldier1979 [14.2K]

Answer:

A procedure according to the norms.

Explanation:

If possible, proceed to fix the leak in no more than 30 days from the moment it was discovered.

Otherwise, during the first 30 days develop a planification to backfit the leak or, if needed, retire the appliance. This should be executed within one year.

7 0
3 years ago
When is an object moving in uniform circular motion?
ad-work [718]
When its tangential speed is constant
<span>Although the speed of an object that has a uniform circular motion is constant, its velocity is </span>not constant<span>. Not only that, but it is actually changing constantly.</span><span>

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6 0
4 years ago
Read 2 more answers
The tailor makes 4 blue shirts for every 3 white shirts he makes. If the tailor makes 12 white shirts in 1 day, how many blue sh
Sati [7]
4 blue = 3 white
x blue = 12 white?

\frac{4 blue}{3 white} =  \frac{x blue}{12 white}

Cross multiply
48 = 3x
x = 16 blue

Another way to do this is figure how many times 3 whites go into 12 whites.
That's 4 times.
So 4 blue x 4 = 16 blue
8 0
4 years ago
Read 2 more answers
A convex lens has a focal length of 16.5 cm. Where on the lens axis should an object be placed in order to get a virtual, enlarg
alexandr402 [8]

Answer:

Object should be placed at a distance, u = 7.8 cm

Given:

focal length of convex lens, F = 16.5 cm

magnification, m = 1.90

Solution:

Magnification of lens, m = -\frac{v}{u}

where

u = object distance

v = image distance

Now,

1.90 = \frac{v}{u}

v = - 1.90u

To calculate the object distance, u by lens maker formula given by:

\frac{1}{F} = \frac{1}{u}+ \frac{1}{v}

\frac{1}{16.5} = \frac{1}{u}+ \frac{1}{- 1.90u}

\frac{1}{16.5} = \frac{1.90 - 1}{1.90u}

\frac{1}{16.5} = \frac{ 0.90}{1.90u}

u = 7.8 cm

Object should be placed at a distance of 7.8 cm on the axis of the lens to get virtual and enlarged image.

6 0
4 years ago
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