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3 years ago

84. Three resitors each of value 30 respectively are connected in a parallel

Physics

1 answer:

kati45 [8]3 years ago

8 0

Answer:

each resistor draws 1/3 of an amp or 0.33333 amps

Explanation:

V = I * R

V = 10 volts

R = 30 ohms

10 = I * 30 Divide by 30

10/30 = I

I = 0.33333

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According to the three laws of planetary motion, planetary orbits are in the shape of a/an

Talja [164]

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4 years ago

An electron is confined in a harmonic oscillator potential well. What is the longest wavelength of light that the electron can a

kipiarov [429]

Answer:

The longest wavelength of light is 209 nm.

Explanation:

Given that,

Spring constant = 74 N/m

Mass of electron $m= 9.11\times10^{-31}\ kg$

Speed of light $c= 3\times10^{8}\ m/s$

We need to calculate the frequency

Using formula of frequency

$f =\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

Where, k= spring constant

m = mass of the particle

Put the value into the formula

$f=\dfrac{1}{2\pi}\sqrt{\dfrac{74}{9.11\times10^{-31}}}$

$f=1.434\times10^{15}\ Hz$

We need to calculate the longest wavelength that the electron can absorb

$\lambda=\dfrac{c}{f}$

Where, c = speed of light

f = frequency

Put the value into the formula

$\lambda =\dfrac{3\times10^{8}}{1.434\times10^{15}}$

$\lambda=2.092\times10^{-7}\ m$

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Hence, The longest wavelength of light is 209 nm.

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3 years ago

How would I calculate the X from a known velocity when launching a ball off a table?

Anon25 [30]

Here are the steps you would need to follow:

#1). Define what 'the 'X is, and how it's related to the ball.
#2). Be clear on how 'the X' is related to the 'known velocity'.
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With this information in front of you, you'll have a much better chance
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With none of it in front of me, I have no chance at all.

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3 years ago

Read 2 more answers

An object has a mechanical energy of 1575 J and a potential energy of 1265 J.

laila [671]

A. 1575 - 1265 = 310J

B. KE 1/2 MV^2

V=√2·KE/M = √2(310)/12 V = 7.2mls

C. PE = 1265 = mgh

h= 1265/mg = 1265/(12)(92) h= 10.8m

A. KE = 1/2 mv^2 0.5(5)(12)^2 KE = 360J

B. PE = mgh = (5)(9.8)(2.6) PE = 127.4J