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8090 [49]
3 years ago
14

Practice: Balance each of the chemical equations below. (Some equations may already be in balance.) In the space to the right, c

lassify the reaction as a synthesis, decomposition, single replacement, or double replacement reaction. A. AgNO3 + KCl ???? AgCl + KNO3 B. H2O + SO3 ???? H2SO4 C. KI + Cl2 ???? KCl + I2 D. NaHCO3 ???? Na2CO3 + H2O + CO2 E. Zn + HCl ???? ZnCl2 + H2 F. BaCl2 + Na2SO4 ???? BaSO4 + NaCl G. C3H8 + O2 ???? CO2 + H2O H. Al + CuCl2 ???? AlCl3 + Cu
Chemistry
1 answer:
vladimir1956 [14]3 years ago
3 0

Explanation:

A. AgNO3 + KCl --> AgCl + KNO3

Reaction is already balanced.

Type = Double Replacement

B. H2O + SO3 --> H2SO4

Reaction is already balanced.

Type = Synthesis

C. KI + Cl2 --> KCl + I2

Balanced Equation = 2KI + Cl2 --> 2KCl + I2

Type = Single Replacement

D. NaHCO3 --> Na2CO3 + H2O + CO2

Balanced Equation = 2NaHCO3 --> Na2CO3 + H2O + CO2

Type = Decomposition

E. Zn + HCl  --> ZnCl2 + H2

Balanced Equation = Zn + 2HCl  --> ZnCl2 + H2

Type = Single Replacement

F. BaCl2 + Na2SO4 --> BaSO4 + NaCl

Balanced Equation =  BaCl2 + Na2SO4 → 2NaCl + BaSO4  

Type = Double Replacement

G. C3H8 + O2 --> CO2 + H2O

Balanced Equation =  C3H8 + 5O2 → 3CO2 + 4H2O  

Type = Single Replacement

H. Al + CuCl2 --> AlCl3 + Cu

Balanced Equation =   2Al + 3CuCl2 → 2AlCl3 + 3Cu  

Type = Single Replacement

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A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.58
Scilla [17]

Answer:

\% O=27.6\%

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}  =0.218molC

- Moles of hydrogen are contained in the 3.922 grams of water:

n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO

Finally, we compute the percent by mass of oxygen:

\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%

Regards.

5 0
4 years ago
A _____ equation is a chemical equation that does not indicate relative amounts of reactants and products. A. balanced B. activi
Alla [95]
A Skeleton equation is a chemical equation that does not indicate relative amounts of reactants and products. Answer: D)
8 0
3 years ago
Sodas are made fizzy by the carbon dioxide ( CO ) dissolved in the liquid. An amount of carbon 2 dioxide equal to about 8.0 L of
eduard

Answer:

A) The number of moles of Carbon dioxide in 2.0 L bottle of soda = 0.325 mole

B) The mass of Carbon dioxide in 2.0 L bottle of soda = 14.3 g

Explanation:

Complete Question

Soda are made fizzy by the carbon dioxide (CO₂) dissolved int he liquid. An amount of carbon dioxide equal to about 8.0 L of carbon dioxide gas at atmospheric pressure and 300.0 K can be dissolved can be dissolved in a 2-L bottle of soda. The molar mass of CO₂ IS 44 g/mol.

A) How many moles of carbon dioxode are in the 2-L? (1L = 0.001 m³)

B) What is the mass of the carbon dioxide in the 2-L bottle of soda?

Solution

Assuming that CO₂ is an ideal gas.

A) The amount of carbon dioxide in 2.0 L of soda bottle is equal to the amount of Carbon dioxide in about 8.0 L of carbon dioxide gas at atmospheric pressure and 300.0 K

From the ideal gas equation, we know that

PV = nRT

P = pressure of the gas = atmospheric pressure = 101,325 Pa

V = volume of the gas = 8.0 L = 0.008 m³

n = number of moles of the ideal gas = ?

R = molar gas constant = 8.314 J/mol.K

T = absolute temperature of the gas in Kelvin = 300 K

101325 × 0.008 = n × 8.314 × 300

n = (101325×0.008) ÷ (8.314 × 300)

n = 0.324993986 = 0.325 mole of Carbon dioxide.

B) The mass of Carbon dioxide in 2.0 L bottle of soda

Mass = (Number of moles) × (Molar mass)

= 0.325 × 44.0

= 14.3 g

Hope this Helps!!!

7 0
3 years ago
0.20dm
Alex_Xolod [135]

Answer:

I don't no sorry. ਕਿਉੁਂਕਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ 478figxigxurRyyv ਸ੍

5 0
3 years ago
Although not usually soluble in plain water, an amphoteric oxide or hydroxide is: 1. soluble in neutral solutions. 2. soluble in
Aleksandr [31]

Answer:

The correct option is: 4. soluble in both acidic and basic solutions

Explanation:

Oxide is a chemical compound formed by an element with oxygen. In such compounds, the oxygen is generally present in the -2 oxidation state.

Whereas, hydroxide is a chemical compound formed by an element with hydroxyl group (-OH).

<em>Oxides and hydroxides of some elements are </em><em>amphoteric</em><em> in nature.</em> <u><em>Such compounds can behave as an acid in basic medium and behave as a base in acidic medium.</em></u>

<u>Therefore, amphoteric oxides and hydroxides are soluble in both acidic and basic solutions.</u>

5 0
4 years ago
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