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nadezda [96]
3 years ago
7

0.20dm

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
5 0

Answer:

I don't no sorry. ਕਿਉੁਂਕਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ 478figxigxurRyyv ਸ੍

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If 125 cal are added to 56,0 g of solid iron, what is the change in temperature of the iron? The specific heat of iron
stealth61 [152]
There is the internet
4 0
2 years ago
Why can't the temperature of an object alone
lukranit [14]

Answer:

It cant

Explanation:

It can not tell because the size of a human and an object to 2 different sizes. Therefor since they are 2 different sizes they can handle different amounts of temperature.

4 0
3 years ago
The electrical conductivities of the following 0.100 M solutions were measured in an apparatus that contained a light bulb as th
Rufina [12.5K]

Answer:

Al(NO₃)₃ >  KI > HF > CH₃OH

Explanation:

The electrical conductivities of the solutions will depend on the concentration of ions in solution.

Al(NO₃)₃ solution contains 0.1 M of Al³⁺ ions and 0.3 M of NO₃⁻ ions

KI solution contains 0.1 M of K⁺ ions and 0.1 M of I⁻ ions

HF solution contains less than 0.1 M of H⁺ ions and less then 0.1 M of F⁻ ions, because the HF acid will not dissociate completely

CH₃OH practically it does not dissociate, so in the solution will not be electrical conductive (comparative with the other solutions)

The solutions in order of decreasing intensity of the bulb are ranked as following:

Al(NO₃)₃ >  KI > HF > CH₃OH

5 0
3 years ago
Middle School science 3 1. Illustrate the position of the Earth, moon, and sun during a lunar eclipse. You may do so by typing a
lilavasa [31]
I hope this helps you

7 0
3 years ago
The reactant concentration in a second-order reaction was 0.560 m after 115 s and 3.30×10−2 m after 735 s . what is the rate con
Aloiza [94]
Use the formula for second order reaction:

\frac{1}{C} = \frac{1}{C_0} + kt

C = concentration at time t 
C0 =  initial conc.
k = rate constant
t = time

1st equation :   \frac{1}{0.56} = \frac{1}{C_0} + 115k

2nd Equation: \frac{1}{0.033} = \frac{1}{C_0} + 735k

Find \frac{1}{C_0} from 1st equation and put it in 2nd equation:

\frac{1}{0.033} = \frac{1}{0.56} - 115k + 735k

\frac{1}{0.033} - \frac{1}{0.56} = 620k

k = 0.046
3 0
3 years ago
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