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LenaWriter [7]
3 years ago
14

Study the image. Warm and cold air fronts with points labeled 1 through 4. 1: cold air entering from the left and moving down. 2

: clouds with rain. 3: warm air entering from the right and moving up. 4: warm air entering from the top left and moving down toward the clouds. Warm and cold air fronts with points labeled 1 through 4. 1: cold air entering from the left and moving down. 2: clouds with rain. 3: warm air entering from the right and moving up. 4: warm air entering from the top left and moving down toward the clouds. At which point is cool air circulating beneath warm air? 1 2 3 4
Chemistry
2 answers:
nata0808 [166]3 years ago
7 0

Answer:

1

Explanation:

NISA [10]3 years ago
4 0

Answer:

1

Explanation:

Edge 2021

You might be interested in
Why do some transition metals have multiple oxidation states? Select the correct answer from each drop down menu
Vlad [161]

Answer:

Transition metals can have multiple oxidation states because of their electrons. The transition metals have several electrons with similar energies, so one or all of them can be removed, depending the circumstances. This results in different oxidation states. please mark me as brainellist

4 0
2 years ago
Use the periodic table to identify the element with the electron configuration 1s²2s²2p⁴. Write its orbital diagram, and give th
natta225 [31]

Answer:

1. Orbital diagram

2p⁴   ║ ↑↓ ║  "↑"  ║   ↑

2s²    ║ ↑↓ ║

1s²     ║ ↑↓ ║

2. Quantum numbers

  • <em>n </em>= 2,
  • <em>l</em> = 1,
  • m_{l} = 0,
  • m_{s} = +1/2

Explanation:

The fill in rule is:

  • Follow shell number: from the inner most shell to the outer most shell, our case from shell 1 to 2
  • Follow the The Aufbau principle, 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p
  • Hunds' rule: Every orbital in a sublevel is singly occupied before any orbital is doubly occupied. All of the electrons in singly occupied orbitals have the same spin (to maximize total spin).

So, the orbital diagram of given element is as below and the sixth electron is marked between " "

2p⁴   ║ ↑↓ ║  "↑"  ║   ↑

2s²    ║ ↑↓ ║

1s²     ║ ↑↓ ║

The quantum number of an electron consists of four number:

  • <em>n </em>(shell number, - 1, 2, 3...)
  • <em>l</em> (subshell number or  orbital number, 0 - orbital <em>s</em>, 1 - orbital <em>p</em>, 2 - orbital <em>d...</em>)
  • m_{l} (orbital energy, or "which box the electron is in"). For example, orbital <em>p </em>(<em>l</em> = 1) has 3 "boxes", it was number from -1, 0, 1. Orbital <em>d</em> (<em>l </em>= 2) has 5 "boxes", numbered -2, -1, 0, 1, 2
  • m_{s} (spin of electron), either -1/2 or +1/2

In our case, the electron marked with " " has quantum number

  • <em>n </em>= 2, shell number 2,
  • <em>l</em> = 1, subshell or orbital <em>p,</em>
  • m_{l} = 0, 2nd "box" in the range -1, 0, 1
  • m_{s} = +1/2, single electron always has +1/2
3 0
3 years ago
When sodium chloride reacts with iron it forms sodium and iron (ll) Chloride. Write down the balanced equation and classify it \
BartSMP [9]

Answer:

NaCl + Fe2+  ---> FeCl2 + Na+

Single replacement

Explanation:

Na is replaced by Fe2+ to form FeCl2, and that is the only replacement. Thus, it is single replacement.

7 0
3 years ago
If the concentration of a KCl solution is 16.0% (m/v), then the mass of KCl in 26.0 mL of solution is ________.
melomori [17]

Answer:

The correct answer is 4.16 grams.

Explanation:

Based on the given information, the concentration of KCl solution is 16 % m/v, which means that 100 ml of the solution will contain 16 grams of KCl.

The molarity of the solution can be determined by using the formula,

M = weight/molecular mass × 1000/Volume

The molecular mass of KCl is 74.6 grams per mole.

M = 16/74.6 × 1000/100

M = 16/74.6

M = 2.14 M

Now the weight of KCl present in the solution of 26 ml will be,

2.14 = Wt./74.6 × 1000 /26

Wt. = 4.16 grams

3 0
2 years ago
Please Help, will give 30 points! The following data was collected when a reaction was performed experimentally in the laborator
Sedaia [141]

Answer:

9 moles of NaNO3.

Explanation:

The balanced equation for the reaction is given below:

Al(NO3)3 + 3NaCl —> 3NaNO3 + AlCl3

Next, we shall determine the number of mole of Al(NO3)3 and NaCl that reacted and the number of mole of NaNO3 produced from the balanced equation.

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl to produce 3 moles of NaNO3.

Next, we shall determine the limiting reactant.

The limiting reactant can be obtained as follow:

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl.

Therefore, 4 moles of Al(NO3)3 will react with = (4 x 3)/1 = 12 moles of NaCl.

From the calculations made above, we can see that it will take a higher amount i.e 12 moles than what was given i.e 9 moles of NaCl to react completely with 4 moles of Al(NO3)3.

Therefore, NaCl is the limiting reactant and Al(NO3)3 is the excess reactant.

Finally, we shall determine the maximum amount of NaNO3 produced from the reaction.

In this case, the limiting reactant will be used as it will produce the maximum amount of NaNO3 since all of it is consumed by the reaction.

The limit reactant is NaCl and the maximum amount of NaNO3 produced can be obtained as follow:

From the balanced equation above,

3 moles of NaCl reacted to produce 3 moles of NaNO3.

Therefore, 9 moles of NaCl will also react to produce 9 moles of NaNO3.

From the calculations made above, the maximum amount of NaNO3 produced is 9 moles

6 0
3 years ago
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