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LenaWriter [7]
3 years ago
14

Study the image. Warm and cold air fronts with points labeled 1 through 4. 1: cold air entering from the left and moving down. 2

: clouds with rain. 3: warm air entering from the right and moving up. 4: warm air entering from the top left and moving down toward the clouds. Warm and cold air fronts with points labeled 1 through 4. 1: cold air entering from the left and moving down. 2: clouds with rain. 3: warm air entering from the right and moving up. 4: warm air entering from the top left and moving down toward the clouds. At which point is cool air circulating beneath warm air? 1 2 3 4
Chemistry
2 answers:
nata0808 [166]3 years ago
7 0

Answer:

1

Explanation:

NISA [10]3 years ago
4 0

Answer:

1

Explanation:

Edge 2021

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During a lab exam a student looked through the microscope and identified the following cell parts: circular DNA, ribosomes, cell
notsponge [240]

Answer:

The correct answer to this question is a prokaryotic cell.

Explanation:

Prokaryotes have circular DNA and a cell wall, whereas eukaryotes have their DNA packaged into chromosomes and may not have a cell wall (as is the case in animal cells).

Hope this helps!

5 0
3 years ago
Equal volumes of two solutions, one containing a strong acid at pH 2 and the other containing a strong base at pH 12, are mixed.
mash [69]

Answer:

7  

Explanation:

Assume we have 1 L of each solution.

Solution 1

\text{[H$^{+}$]}= 10^\text{-pH} \text{ mol/L} = 10^{\text{-2}} \text{ mol/L}\\ \text{ moles of H}^{+} = \text{ 1 L solution} \times \dfrac{10^{-2}\text{ mol H}^{+}}{\text{1 L solution}} = 10^{-2}\text{ mol H}^{+}

Solution 2

pH = 12

pOH = 14.00 - pOH = 14.00 - 12 = 2.0

\text{[OH$^{-}$]}= 10^\text{-pOH} \text{ mol/L} = 10^{\text{-2}} \text{ mol/L}\\ \text{ moles of OH}^{-} = \text{ 1 L solution} \times \dfrac{10^{-2}\text{ mol OH}^{-}}{\text{1 L solution}} = 10^{-2}\text{ mol OH}^{-}

3. pH after mixing

               H⁺  +  OH⁻ ⟶ H₂O

I/mol:     10⁻²    10⁻²  

C/mol:   -10⁻²   -10⁻²

E/mol:      0        0

The H⁺ and OH⁻ have neutralized each other. The pH will be that of pure water.

pH = 7

8 0
3 years ago
13. What is the frequency of a wave that has a wavelength of 2.73 x 10-7m?​
ella [17]

Answer:

f = 1.09 × 10¹⁵ Hz

Explanation:

Given data:

Frequency of wave = ?

Wavelength of wave = 2.73 ×10⁻⁷ m

Solution:

Formula:

Speed of light = frequency × wavelength

speed of light = 3× 10⁸ m/s

by putting values,

3× 10⁸ m/s = f × 2.73 ×10⁻⁷ m

f = 3× 10⁸ m/s  / 2.73 ×10⁻⁷ m

f = 1.09 × 10¹⁵s⁻¹

s⁻¹ = Hz

f = 1.09 × 10¹⁵ Hz

4 0
3 years ago
What reaction type is N2 + O2 ---> 2 NO
zmey [24]

Answer:

decomposition: the reactant is breaking down into its constituent elements.

(hope this helps)!

Explanation:

8 0
3 years ago
PH of 0,035M HCl? How to count if your calculator hasn't got -lg?
IrinaK [193]

<u>Given information:</u>

Concentration of HCl = 0.035 M

<u>To determine:</u>

pH of the solution

<u>Explanation:</u>

Hydrochloric acid, HCl is a strong acid. It will completely dissociate to give H+ and Cl- ions

HCl → H+ + Cl-

Hence the concentration of H+ = Cl- = 0.035M

Now, pH measures the strength of H+ ions in a given solution. It is expressed as:

pH = -log[H+]

pH (HCl) = -log(0.035) = 1.46

Ans: pH of 0.035M HCl is 1.46

6 0
3 years ago
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