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LenaWriter [7]
3 years ago
14

Study the image. Warm and cold air fronts with points labeled 1 through 4. 1: cold air entering from the left and moving down. 2

: clouds with rain. 3: warm air entering from the right and moving up. 4: warm air entering from the top left and moving down toward the clouds. Warm and cold air fronts with points labeled 1 through 4. 1: cold air entering from the left and moving down. 2: clouds with rain. 3: warm air entering from the right and moving up. 4: warm air entering from the top left and moving down toward the clouds. At which point is cool air circulating beneath warm air? 1 2 3 4
Chemistry
2 answers:
nata0808 [166]3 years ago
7 0

Answer:

1

Explanation:

NISA [10]3 years ago
4 0

Answer:

1

Explanation:

Edge 2021

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2 years ago
Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
yulyashka [42]

<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

3 0
3 years ago
Please help me to do this assignment
kirill [66]

Answer:

1. Objective

2. Objective

3. Opinion

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6. Opinion

7. Opinion (I think.)

8. Opinion (I think.)

Explanation:

7 0
3 years ago
Which type of changes are melting, freezing, and boiling?​
tatiyna

Answer:

Adding heat.

Decreasing and increasing temperatures.

Explanation:

4 0
2 years ago
Read 2 more answers
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