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quester [9]
2 years ago
11

A movie theater manager of a small theater sells two sizes of popcorn at the concession stand. A jumbo popcorn has a profit of $

4 and a mini popcorn has a profit of $3. The manager knows the maximum number of popcorn boxes that will fit in the concession stand, the cost of making the popcorn, and the minimum number of boxes he wants to sell each day. Let j represent the number of jumbo popcorns sold and let m represent the number of mini popcorns sold. What is the objective function, and how can it be used to maximize the profit based on the the given conditions?
Mathematics
1 answer:
NeX [460]2 years ago
5 0

j4 + m3 = p

If you multiply j, which is the number of jumbo popcorns sold by its price, you are given the profit of the Jumbo boxes for a single day. If you multiply m, which is the number of mini popcorns sold by its price, you are given the profit of the Mini boxes for a single day. If you add the profits from both boxes together... you are given p, which is the total profit for the day.

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2/4-6 ÷ 1/3 + 2
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The ratio of the lengths of the corresponding sides of two rectangles is 8:3. The area of the larger rectangle is 320 ft2. What
cluponka [151]
The area of the smaller rectangle is 320*3/8=120 ft2
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3 years ago
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There are 53 regular pencils in the box and some colored pencils in the box. There are a total of 84 pencils. How many colored p
vodka [1.7K]

Let be "x" the number of colored pencils in the box.

According to the information given in the exercise, there are 84 pencils in the box and 53 of them are regular pencils.

Knowing this information, you can set up the following equation:

x+53=84

Finally, you have to solve for the variable "x" in order to find its value. In order to do this, you can apply the Subtraction property of equality by subtracting 53 from both sides of the equation:

\begin{gathered} x+53-(53)=84-(53) \\ x=31 \end{gathered}

The answer is: There are 31 colored pencils in the box.

7 0
1 year ago
Help me and ill mark branilest for first person to answer CORRECTLY. A histogram is being made for the following list of data. I
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So to put them in intervals of 5 you would have:
70-74
75-79
80-84
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In these intervals you would have:
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80-84: 81
85-89: 86, 86, 87
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The second interval is 75-79 where there is only one number. Therefore the frequency will be 1.
The correct answer is A. Hope this helps! :)
5 0
2 years ago
Complete the square to write the quadratic expression in vertex form.
Anvisha [2.4K]

Answer:

1. (x - 3)² = 8

2. (x + 2)² = 3

3. (x + 6)² = $ \frac{101}{2} $

4. (x + 3)² = 27

5. (x + 4)² = 13

6.  $ \bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9} $

Step-by-step explanation:

Completion of Square: $ (x - a) ^2 = x^2 - 2ax + a^2 $

In the following problems the terms in the RHS of the above equation may be missing. We balance the equation. Simplify it and re write it in terms of LHS.

1. x² - 6x + 1 = 0

Taking the constant term to the other side, we get:

x² - 6x = - 1

⇒ x² - 2(3)x = -1

⇒ x² -2(3)x + 9 = - 1 + 9  [Adding 9 to both the sides]

⇒ x² -2(3)x + 3² = 8

⇒ (x - 3)² = 8 is the answer.

2. 3x² + 12x + 3 = 0

Note that the co-effecient of x² is not 1. We make it 1, by dividing the whole equation by 3. And then proceed like the previous problem.

3x² + 12x = -3

Dividing by 3 through out, x² + 4x = - 1

⇒ x² + 2(2) + 4 = -1 + 4

⇒ x² +2(2) + 2² = 3

⇒ (x + 2)² = 3 is the answer.

3. 2x² + 24x = 29

x² + 12x = $ \frac{29}{2} $

⇒ x² + 2(6)x + 36 = $ \frac{29}{2} $ + 36

⇒ x² + 2(6)x + 6² = $ \frac{29 + 72}{2} $

⇒ (x + 6)² = $ \frac{101}{2} $ is the answer.

4. x² + 6x - 18 = 0

x² + 6x = 18

⇒ x² + 2(3)x = 18

⇒ x² + 2(3)x + 9 = 18 + 9

⇒ x² + 2(3)x + 3² = 27

⇒ (x + 3)² = 27 is the answer.

5. x² + 8x + 3 = 0

x² + 8x = -3

⇒ x² + 2(4)x = -3

⇒ x² + 2(4)x + 16 = - 3 + 16

⇒ x² + 2(4)x + 16 = 13

⇒ (x + 4)² = 13 is the answer.

6. 9x² - 30x + 6 = 0

9x² - 30x = - 6

⇒ x² $ - \frac{30}{9} $ x = - 6

$ \implies x^2 -2 \bigg( \frac{15}{9} \bigg )x + \frac{225}{81} = - 6 + \frac{225}{81} $

$ \implies x^2 - 2\bigg( \frac{15}{9} \bigg ) x + \bigg ( \frac{15}{9} \bigg ) ^2 = \frac{261}{81} $

$ \bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9} $ is the answer.

6 0
3 years ago
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