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3 years ago

Science fiction movies that include explosion sound effects for battles in space are not scientifically correct. Why is this?

Physics

1 answer:

Reil [10]3 years ago

6 0

B. There is not enough matter in space to transmit sound waves.

Explanation:

Sound waves are created when there is a vibration of the particles in a medium. For example, our voice is an example of sound wave: when we speak, the molecules of air around us start vibrating, producing regions of higher concentration of molecules (called compressions) and of lower concentration (called rarefactions). It is clear from this definition that sound waves can only propagate if there is a physical medium: such as a gas, a liquid or a solid, but sound waves cannot propagate through empty space.

Since space is almost empty, the correct choice is

B. There is not enough matter in space to transmit sound waves.

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HELP ASAP

kipiarov [429]

Answer:

This can be part of your paragraph.

Explanation:

From the cornea, the light passes through the pupil. The iris, or the colored part of your eye, controls the amount of light passing through. From there, it then hits the lens. This is the clear structure inside the eye that focuses light rays onto the retina.

4 0

3 years ago

A solar cell, 3.0 cm square, has an output of 350 mA at 0.80 V when exposed to full sunlight. A solar panel that delivers close

Vesna [10]

Answer:

You will need 450 cells (3 cm each) to meet the voltage/current requirement.

The panel must be 3 cells in one side, by 150 cell in another side. 1350 cm^2 or 0.135 m^2. They must be connected 3 in row in parallel (to add current), then each of the former group must be connected in series to meet the voltage, so it would be 150 rows of connected in series.

The panel can be optimized using a voltage inverter, to convert current to voltage. In this way, less cells can be used achieving the same output specs.

Explanation:

To meet the voltage:

120 [v] required voltage

0.8 [v] voltage of each cell

$\frac{120}{0.8} =150[v]\\$

So we need 150 cells in series for the voltage.

To meet the current

1.0 [A] Required current

350[mA]=0.35[A] cell current

1/0.35=3 cell So we need 3 cells in parallel to add the currents and meet the requirement.

See the attached figure

8 0

3 years ago

When Earth runs into the dust trail left behind by a comet that is orbiting the Sun, Earth experiences a _____.

tekilochka [14]

The answer to this question is: C) Meteor Shower

7 0

3 years ago

Read 2 more answers

Which of the following provides evidence that Earth's Moon is rotating and revolving at the same rate?

kkurt [141]

B. We can see only one side of the Moon from Earth.

( we only see one side of the moon because the moon rotates around the Earth)

6 0

3 years ago

You drop a steel ball bearing, with a radius of 2.40 mm, into a beaker of honey. Note that honey has a viscosity of 6.00 Pa/s an

Stells [14]

Answer:

The “terminal speed” of the ball bearing is 5.609 m/s

Explanation:

Radius of the steel ball R = 2.40 mm

Viscosity of honey η = 6.0 Pa/s

$\text { Viscosity has Density } \sigma=1360 \mathrm{kg} / \mathrm{m}^{3}$

$\text { Steel has a density } \rho=7800 \mathrm{kg} / \mathrm{m}^{3}$

$\left.\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2} \text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^{2} \text { on Earth }\right)$

While calculating the terminal speed in liquids where density is high the stokes law is used for viscous force and buoyant force is taken into consideration for effective weight of the object. So the expression for terminal speed (Vt)

$V_{t}=\frac{2 \mathrm{R}^{2}(\rho-\sigma) \mathrm{g}}{9 \eta}$

Substitute the given values to find "terminal speed"

$\mathrm{V}_{\mathrm{t}}=\frac{2 \times 0.0024^{2}(7800-1360) 9.8}{9 \times 6}$

$\mathrm{V}_{\mathrm{t}}=\frac{0.0048 \times 6440 \times 9.8}{54}$

$\mathrm{V}_{\mathrm{t}}=\frac{302.9376}{54}$

$\mathrm{V}_{\mathrm{t}}=5.609 \mathrm{m} / \mathrm{s}$

The “terminal speed” of the ball bearing is 5.609 m/s

7 0

3 years ago