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svp [43]
3 years ago
14

Express in words AND mathematically the relationship between… Period and frequency

Physics
1 answer:
castortr0y [4]3 years ago
6 0
Frequency = how many waves you get per sec
Period = how long each wave takes

Period = 1/frequency
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If the scaled-up man now stands on one leg, what fraction of the tensile strength is the stress on the femur?.
Firdavs [7]

The new cross sectional area and tensile stress is mathematically given as

A=4.8*10^{-4}m^2

X=14:100

<h3>Cross sectional area and stress on the femur</h3>

Question Parameters:

To see why this must be so, recall, that the stress on the femur for a man standing on one leg is 1.4%

we scale this man up by a factor of 10 in all dimensions

that a 70 kg person has a femur with a cross-section area

a)

Generally the New cross sectional area  is mathematically given as

100A=100*4.8*10^{-4}

A=4.8*10^{-4}m^2

b)

From the initial statement we see that  the fraction of the tensile strength is the stress on the femur  and will be

X=\frac{14}{100}

X=14$

X=14:100

For more information on fraction

brainly.com/question/1301963

Complete Question

Larger animals have sturdier bones than smaller animals. A mouse's skeleton is only a few percent of its body weight, compared to 16% for an elephant. To see why this must be so, recall, that the stress on the femur for a man standing on one leg is 1.4% of the bone's tensile strength. Suppose we scale this man up by a factor of 10 in all dimensions, keeping the same body proportions. (Assume that a 70 kg person has a femur with a cross-section area (of the cortical bone) of 4.8 x 10-4m², a typical value.)

Part A

Both the inside and outside diameter of the femur, the region of cortical bone, will increase by a factor of 10. What will be the new cross-section area? Express your answer using two significant figures.

Part B

If the scaled-up man now stands on one leg, what fraction of the tensile strength is the stress on the femur?

8 0
2 years ago
What does it mean when work is positive?
dmitriy555 [2]

Answer:

When force and displacement are in the same direction, the work performed on an object is said to be positive work. Example: When a body moves on the horizontal surface, force and displacement act in the forward path. The work is done in this case known as Positive work.

Explanation:

Hope this helps you

5 0
3 years ago
Read 2 more answers
Calculate the relativistic speed of a particle at a time 6 s after it star t = 0 s . The mass of the particle is 6 × 10-2 kg and
Mars2501 [29]

Answer:

The relativistic speed of a particle is 0.0333\times10^{-5}c

Explanation:

Given that,

Time = 6 sec

Force = 1

Mass of the particle m=6\times10^{-2}\ kg

We need to calculate the acceleration

Using formula of acceleration

a = \dfrac{F}{m}

Put the value into the formula

a=\dfrac{1}{6\times10^{-2}}

a=16.67\ m/s^2

We need to calculate the velocity after 6 sec

Using equation of motion

v = u+at

Put the value

v=0+16.67\times6

v=100\ m/s

The velocity in term of c

v=\dfrac{100c}{3\times10^{8}}

v=3.333\times10^{-7}c

v=0.0333\times10^{-5}c

Hence, The relativistic speed of a particle is 0.0333\times10^{-5}c

6 0
3 years ago
A counterflow double-pipe heat exchanger is used to heat water from 20°C to 80°C at a rate of 1.2 kg/s. The heating is to be com
bixtya [17]

Answer:L=109.16 m

Explanation:

Given

initial temperature =20^{\circ}C

Final Temperature =80^{\circ}C

mass flow rate of cold fluid \dot{m_c}=1.2 kg/s

Initial Geothermal water temperature T_h_i=160^{\circ}C

Let final Temperature be T

mass flow rate of geothermal water \dot{m_h}=2 kg/s

diameter of inner wall d_i=1.5 cm

U_{overall}=640 W/m^2K

specific heat of water c=4.18 kJ/kg-K

balancing energy

Heat lost by hot fluid=heat gained by cold Fluid

\dot{m_c}c(T_h_i-T_h_e)= \dot{m_h}c(80-20)

2\times (160-T)=1.2\times (80-20)

160-T=36

T=124^{\circ}C

As heat exchanger is counter flow therefore

\Delta T_1=160-80=80^{\circ}C

\Delta T_2=124-20=104^{\circ}C

LMTD=\frac{\Delta T_1-\Delta T_2}{\ln (\frac{\Delta T_1}{\Delta T_2})}

LMTD=\frac{80-104}{\ln \frac{80}{104}}

LMTD=91.49^{\circ}C

heat lost or gain by Fluid is equal to heat transfer in the heat exchanger

\dot{m_c}c(80-20)=U\cdot A\cdot (LMTD)

A=\frac{1.2\times 4.184\times 1000\times 60}{640\times 91.49}=5.144 m^2

A=\pi DL=5.144

L=\frac{5.144}{\pi \times 0.015}

L=109.16 m

6 0
3 years ago
The solar system involves the revolution of two planets around it.true/false.​
zhuklara [117]

Answer:

false

Explanation:

all planets revolve around the solar system

hope this is clear enough answered

3 0
3 years ago
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