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svp [43]
3 years ago
14

Express in words AND mathematically the relationship between… Period and frequency

Physics
1 answer:
castortr0y [4]3 years ago
6 0
Frequency = how many waves you get per sec
Period = how long each wave takes

Period = 1/frequency
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How can you use the density of an object to predict whether it will sink or float?
Bas_tet [7]

Answer:

Explanation:

If an object has a higher density than the fluid it is in (fluid can mean liquid or gas), it will sink. If it has a lower density, it will float. Density is determined by an object's mass and volume. If two objects take up the same volume, but have one has more mass, then it also has a higher density.

7 0
3 years ago
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You drive a car 640 m to the east, then 340 m to the north what is the magnitude of your displacement
mixer [17]

Magnitude of displacement = \sqrt{640^2 + 340^2}

Adding the squares gives displacement = \sqrt{525,200}

Displacement =  \sqrt{525,200} ≈ 724.7m

6 0
3 years ago
What is the source of the radioactive nuclei present in spent fuel rods?
Debora [2.8K]
The answer is <span>nuclear fission.  T</span>he source of the radioactive nuclei present in spent fuel rods is nuclear fission.  Nuclear fission<span> is the </span>process<span> in which a large nucleus splits into two smaller nuclei with the release of energy. </span>
6 0
3 years ago
Assignments
sladkih [1.3K]

Hello there!

I hope you and your family are staying safe and healthy during this unprecendented time.

A) What is the work done?

Answer: We need to use the formula

w=-F_f(d)

w=-(35)(20)

w=-700J

B) What is the work done on the cart by the gravitational force?  

Alright, we know that the gravitional force is perpendicular to the diplacement. Therefore, we gonna use the following formula:

w=Fdcos90

w=0

C) What is the work done on the cart by the shopper?

This is the easier part, since we already know that the work done by the shopper is the same as the work done by the friction force

W shopper + W friction = 0\\W shopper = W-friction \\W shopper = 700J

D) Find the force the shopper exerts, using energy considerations.

F_f+Fcos25=0\\-35+Fcos25=0\\F=38.6N

E) What is the total work done?

You just need to add them:

w=wshopper+wfriction\\w=0

4 0
3 years ago
An object is placed to the left of a convex mirror, such that the object-to-image distance is 140 cm.
labwork [276]

Answer:

The focal length of the mirror is 52.5 cm.

Explanation:

Given that,

Object to Image distance d = 140 cm

Image distance v= 35 cm

We need to calculate the object distance

u = d-v

u = 140-35=105\ cm

We need to calculate the focal length

Using formula of mirror

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

Put the value into the formula

\dfrac{1}{f}=\dfrac{1}{-105}+\dfrac{1}{35}

\dfrac{1}{f}=\dfrac{2}{105}

f=52.5\ cm

Hence, The focal length of the mirror is 52.5 cm.

6 0
3 years ago
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