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jekas [21]
3 years ago
9

Describe the motion of a skydiver from the time he jumps to the time he lands safely on the ground

Physics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

The skydiver accelerates at the beginning, while later he continues at constant velocity

Explanation:

There are two forces acting on the skydiver during its fall:

  • The force of gravity, which is constant, of magnitude mg, where m is the mass of the skydiver and g is the acceleration of gravity (9.8 m/s^2 downward)
  • The air resistance, whose magnitude is proportional to the  speed of the skydiver: F_r\propto v, and which acts upward

At the beginning of its fall, the speed of the skydiver is small, therefore at the beginning the air resistance is negligible, and therefore the skydiver is accelerated downward with an acceleration of

g=9.8 m/s^2

However, as the skydiver falls, he gains speed; therefore, the magnitude of the air resistance increases. The net force acting on the skydiver is

F_{net}=mg-F_r

As the air resistance increases, the net force decreases: therefore, the acceleration of the skydiver decreases. Eventually, he will reach a speed at which the air resistance becomes equal to the force of gravity:

mg=F_r

when this occurs, the acceleration of the skydiver will become zero, so he will continue his fall at a constant velocity: this value of the velocity is called terminal velocity.

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

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6 0
3 years ago
Read 2 more answers
A frog falls from its rainforest tree. If we ignore wind resistance, (a) how much time does it take the frog to fall a distance
gtnhenbr [62]

Answer:

Explanation:

a) Using the equation of motion

S = ut + 1/2gt²

S is the distance of fall

g is the acceleration due to gravity

t is the time taken

Given S = 12.0m, g = 9.81m/s^2, un= 0m/s

12 = 0+1/2(9.81)t²

12 = 4.905t²²²

t² = 12/4.905

t² = 2.446

t = √2.446

t = 1.56secs

b) To determine how fast is the frog falling at this point, we need to calculate the speed of the frog. Using the equaton v = u+gt

v = 0+9.81(1.56)

v = 15.34m/s

Hence the frog is falling at the rate of 15.34m/s

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3 years ago
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3 years ago
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3 years ago
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Umnica [9.8K]

Answer:

Explanation:

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3 years ago
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