Answer:
1,000,000 particles of tap water would be for every 75 particles of FeCl3
Explanation:
sample of tap water contains 75 ppm aqueous FeCl3.
i.e sample of water is 75 particular per million aqueous FeCl3
Sample of water = 75/1000000 particular of FeCl3
x particular of water = 75 particular of FeCl3
To find the value of x, we cross multiply
Therefore we have:
75 = 75/1,000,000X
X = 75 / (75/1000000)
X = 75 x 1000000/75
X = 1,000,000.
1,000,000 particles of tap water would be for every 75 particles of FeCl3
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
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