Answer
Q=4479.8 cal
Procedure
To solve the problem you will need to use the specific heat formula
Where;
Q=heat energy
m=mass
c=specific heat capacity
ΔT=change in temperature
Assuming that the heat released from the cracker of unknown material is equal to the heat absorbed by the water, then we can use the c and m for water in our calculations.
Substituting the values in our equation we have
Finally, transform the J to cal
Answer:, formaldehyde
Explanation:
each molecule of which consists of one carbon atom, two hydrogen atoms, and one oxygen atom, has the molecular formula CH2O, which is identical to the empirical formula of glucose.
If this helps.
<span>The balance format is
4NH3+ 5O2 -------> 4NO + 6H2O </span>
If you are given the number of
moles of sodium bicarbonate, use the balanced chemical equation. The molar mass
of the acetic acid is 60 grams per mole. Using stochiometric balance.
Number of moles of acetic acid =
3 moles NaHCO3 (1 mol CH3COOH/1 mol NaHCO3) = 3 moles of acetic acid
Grams of acetic acid = 3 moles
of CH3COOH (60 g CH3COOH/1 mol CH3COOH) = <span>180 grams of acetic acid</span>
Answer:
Vol of 4 moles CO₂(g) at STP = 89.6 Liters
Explanation:
STP
P = 1 Atm
V =
T = 0°C = 273 K
n = 4 moles
R = 0.08206 L·Atm/mol·K
Using Ideal Gas Law PV = nRT => V = nRT/P
V = (4 moles)(0.08206 L·Atm/mol·K)(273 K)/(1 Atm) = 89.6 Liters
