I attached da picture

Mathematics

1 answer:

Svetach [21]2 years ago

7 0

1. withdrawals would be negative, deposits would be positive
2. -102.47
3. yes, because he spent $40 in addition to his -$62.47 balance. this would make his balance come to -$2.47

You might be interested in

Ronny, Celina, Jack, and Michelle together placed a total of 20 brownies on a tray. Ronny placed 0.15 of the brownies, Celina pl

Marat540 [252]

To answer the question above, evaluate the number of cookies each of them placed on a tray. The calculations are shown below,

Ronny C1 = 0.15 x 20 = 3
Celina C2 = 3
Jack C3 = 0.30 x 20 = 6
Michelle C4 = 20 - (3 + 3 + 6) = 8

From the calculation above, Michelle placed the most number of brownies on the tray.

3 0

3 years ago

Read 2 more answers

Carl deposited $5,142 into a savings account 20 years ago. The account has an interest rate of 3.8% and the balance is currently

Aleksandr [31]

Here is the formula you'll need
Total = Principal * (1 + (rate/n))^n*years
I don't know how to solve that for "n" so we'll use trial and error.

If compounded annually, total = 10,841.24 
If compounded quarterly, total = 10,955.64 
If compounded monthly, total = 10,981.82 
If compounded daily, total = 10,994.58 
Therefore the answer is "A", daily.

Source:
http://www.1728.org/compint3.htm

3 0

3 years ago

Based on the Nielsen ratings, the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the are

Nastasia [14]

Answer:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

$z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{100}}}=-1.017$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

$\hat p=0.36$ estimated proportion with the survey

$p_o=0.41$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is lower than 0.41.:

Null hypothesis: $p\geq 0.41$

Alternative hypothesis: $p < 0.41$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .