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OlgaM077 [116]
3 years ago
7

An isosceles triangle has an angle that measures 116°. Which other angles could be in that isosceles triangle? Choose all that a

pply.
Mathematics
2 answers:
Arisa [49]3 years ago
8 0

Answer:

yehsbknkdndwnondidmidmndimdkdmdmkd djdndjndjdnjdnjdnjdndjndjndjdjdnjdnjdndjndndjndjdnjdnjdndjndjndjndjdnjdndjnddndjndjdnjdnjdndjdnjdnjdndjndjdjdieheiydgduddiddugdhdbjddkjdhddbdtdfdtvdhdbdjdndd

Step-by-step explanation:

sorry bud cant help need points

Veseljchak [2.6K]3 years ago
8 0

Answer:

Step-by-step explanation:

since we know that triangles have 180° we know that 116° is two much if it's doubled  2*116 = 232° so that angle has to be the single angle and the left over of 180 - 116  is the left over amount that is even divided into the last two angles so   180 - 116 = 64 / 2 = 32°  so the triangle is made up of  116 + 32 + 32 degree angles

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The equation for the circle below is the x2 + y2=81. what is the length of the circles radius
larisa [96]

Answer:

9

Step-by-step explanation:

Compare your x2 + y2=81 to the following:

                       x^2 + y^2 = 81

The " ^ " symbol indicates exponentiation.

Now compare  x^2 + y^2 = 81 to

                         x^2 + y^2 = r^2.  

This is the standard equation of a circle of radius r centered at the origin, (0,0).  You can see for yourself that 81 must equal r^2.


Taking the square root of 81, we get plus or minus 9.

But the radius must be positive, so we reject the -9 and take +9.

The radius is 9.

8 0
3 years ago
Read 2 more answers
SOLVED
Nastasia [14]
5)
a. The equation that describes the forces which act in the x-direction: 
<span>     Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span>     Fy = 200 * sin 30 </span>

<span>c. The x and y components of the force of tension: </span>
<span>    Tx = Fx = 200 * cos 30  </span>
<span>    Ty = Fy = 200 * sin 30 </span>

d.<span>Since desk does not budge, </span><span>frictional force = Fx
                                                                        = 200 * cos 30 </span>

<span>                                                 Normal force </span><span>= 50 * g - Fy
                                                                       = 50 g - 200 * sin 30 
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction: 
    (200N)cos(30) - F_s = 0

b. The equation that describes the forces which act in the y-direction:
    F_N - (200N)sin(30) - mg = 0

c. The values of friction and normal forces will be:
     Friction force= (200N)cos(30),
     
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N

Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
4 0
4 years ago
Calculate the value of 3x + 4y when x = -6 and y = 5.
MArishka [77]

Answer:

x = -6

-18+4y=0 => 4y=18 =>y=18/4=9/2

Y=5

3x+20=0 => x=3x= -20=> x= -20/3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A rectangles length is 2 in more than its width. The area of the rectangle is 143 square inches. Find the dimensions of the rect
Anastaziya [24]

Answer: The length is 13 inches and the width is 11 inches.

Step-by-step explanation:

Let L represent the length of the rectangle.

Let W represent the width of the rectangle.

The formula for determining the area of a rectangle is expressed as

Area = LW

The area of the rectangle is 143 square inches. This means that

LW = 143 - - - - - - - - - - - - --1

The rectangle's length is 2 in more than its width. This means that

L = W + 2

Substituting L = W + 2 into equation 1, it becomes

W(W + 2) = 143

W² + 2W - 143 = 0

W² + 13W - 11W - 143 = 0

W(W + 13) - 11(W + 13) = 0

W + 13 = 0 or W - 11 = 0

W = - 13 or W = 11

Since the width cannot be negative, it means that W = 11

L = W + 2 = 11 + 2

L = 13

4 0
4 years ago
Suppose that birth weights are normally distributed with a mean of 3466 grams and a standard deviation of 546 grams. Babies weig
Anon25 [30]

Answer:

3.84% probability that it has a low birth weight

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3466, \sigma = 546

If we randomly select a baby, what is the probability that it has a low birth weight?

This is the pvalue of Z when X = 2500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2500 - 3466}{546}

Z = -1.77

Z = -1.77 has a pvalue of 0.0384

3.84% probability that it has a low birth weight

3 0
4 years ago
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