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2 years ago

How many moles of N20 gas would have a volume of 3.8 L at 460 mmHg and 77°C?

Chemistry

1 answer:

Citrus2011 [14]2 years ago

7 0

We are given:

Volume of gas = 3.8 L

Pressure = 460 mmHg

Temperature = 77°c = (77+273)K = 350K

Converting the pressure to atm:

Pressure(in atm) = Pressure(in mmHg) / 760

Pressure = 460/760 = 0.6 atm

Finding the number of moles:

using the ideal gas equation:

PV = nRT [where R is the universal gas constant]

replacing the given values in this equation

(0.6)(3.8) = n(0.082)(350)

n = (0.6*3.8)/(0.082*350)

n = 0.08 moles

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Calculate the energy required to heat 566.0mg of graphite from 5.2°C to 23.2°C. Assume the specific heat capacity of graphite un

maw [93]

Answer:

7.23 J

Explanation:

Step 1: Given data

Mass of graphite (m): 566.0 mg

Initial temperature: 5.2 °C

Final temperature: 23.2 °C

Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)

Q = 7.23 J

6 0

3 years ago

Calcium hydroxide, Ca(OH)2, is an ionic compound with a solubility product constant, Ksp, of 6.5×10–6. Calculate the solubility

kari74 [83]

Answer: The solubility of this compound in pure water is 0.012 M

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

The equation for the ionization of the is given as:

$Ca(OH)_2\rightarrow Ca^{2+}+2OH^-$

By stoichiometry of the reaction:

1 mole of $Ca(OH)_2$ gives 1 mole of $Ca^{2+}$ and 2 mole of $OH^-$

When the solubility of $Ca(OH)_2$ is S moles/liter, then the solubility of $Ca^{2+}$ will be S moles\liter and solubility of $OH^-$ will be 2S moles/liter.

$K_{sp}=[Ca^{2+}][OH^{-}]^2$

$6.5\times 10^{-6}=[S][2S]^2$

$S=0.012M$

Thus solubility of this compound in pure water is 0.012 M

5 0

3 years ago

c. The reaction Br2 (l) --> Br2 (g) has ΔH = 30.91 kJ/mol and ΔS = 93.3 J/mol·K. Use this information to show (within close a

egoroff_w [7]

Answer:

The answer to your question is given below.

Explanation:

From the question given above, the following data were obtained:

Br₂ (l) —> Br₂(g)

Enthalpy change (ΔH) = 30.91 KJ/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

Next, we shall convert 30.91 KJ/mol to J/mol. This can be obtained as follow:

1 KJ/mol = 1000 J/mol

Therefore,

30.91 KJ/mol = 30.91 × 1000

30.91 KJ/mol = 30910 J/mol

Thus, 30.91 KJ/mol is equivalent to 30910 J/mol.

Finally, we shall determine the boiling temperature of bromine. This can be obtained as follow:

Enthalpy change (ΔH) = 30910 J/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

ΔS = ΔH / T

93.3 = 30910 / T

Cross multiply

93.3 × T = 30910

Divide both side by 93.3

T = 30910 / 93.3

T = 331.29 K

Thus, the boiling temperature of bromine is 331.29 K

6 0

3 years ago

NEED HELP!! WILL NAME THE BRAINIEST!!!

Paladinen [302]

Answer:

elements

Explanation:

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2 years ago

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How you find a unknown element (just with the atomic emission spectrum)

Sliva [168]

Each natural element has a characteristic light spectrum that helps identify it in samples of unknown substances. Spectroscopy is the practice of examining spectra and comparing them to those of known elements. Using spectroscopy methods, scientists can identify pure substances or compounds and the elements in them.

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2 years ago