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dusya [7]
2 years ago
10

How many moles of N20 gas would have a volume of 3.8 L at 460 mmHg and 77°C?

Chemistry
1 answer:
Citrus2011 [14]2 years ago
7 0

<u>We are given:</u>

Volume of gas = 3.8 L

Pressure = 460 mmHg

Temperature = 77°c = (77+273)K = 350K

<u>Converting the pressure to atm:</u>

Pressure(in atm)  = Pressure(in mmHg) / 760

Pressure = 460/760 = 0.6 atm

<u>Finding the number of moles:</u>

using the ideal gas equation:

PV = nRT                                         [where R is the universal gas constant]

<em>replacing the given values in this equation</em>

(0.6)(3.8) = n(0.082)(350)

n = (0.6*3.8)/(0.082*350)

n = 0.08 moles

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Explanation:

We are given that  for the equilibrium

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9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

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