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hram777 [196]
3 years ago
7

Brainliest for correct answer!

Chemistry
2 answers:
My name is Ann [436]3 years ago
4 0
The answer is salad..........
Gwar [14]3 years ago
4 0
Salad hope this helps
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A certain substance X has a normal freezing point of -10.1 degree C and a molal freezing point depression constant K_f = 5.32 de
kirill115 [55]

Answer: -15.4^00C

Explanation:

T^0_f-T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_f = boiling point of solution = ?

T^o_f = boiling point of solvent (X) = -10.1^oC

k_f = freezing point constant  = 5.32^oC/kgmol

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte like urea)

= mass of solute (urea) = 29.82 g

= mass of solvent (X) = 500.0 g

M_2 = molar mass of solute (urea) = 60 g/mol

Now put all the given values in the above formula, we get:

(-10.1-(T_f))^oC=1\times (5.32^oC/m)\times \frac{(29.82g)\times 1000}{60\times (500.0g)}

T_f=-15.4^0C

Therefore, the freezing point of  solution is -15.4^0C

7 0
3 years ago
If a reaction starts with 0.480 mol Mg how many moles of silver are produced
cupoosta [38]
The ratio for mg and ag is 1:2 therefore, 0.96 mole silver is produced, use the conversation method.
5 0
4 years ago
7. What must you do before you make a hypothesis?
almond37 [142]

Answer:

Ask a question?

Explanation:

look at the scientific method uwu

6 0
3 years ago
24. The air in a small 250 cm birthday balloon is at a pressure of 760 torr. A boy sits on it at
kvv77 [185]

Answer:

1.14atm

Explanation:

Given parameters:

V1 = 250cm³ ;

              1000cm³ = 1dm³;  so this is 0.25dm³

P1  = 760torr

            760torr  = 1atm

       

V2  = 220cm³ ; 0.22dm³

Unknown:

New pressure = ?

Solution:

To solve this problem, we apply Boyle's law and we use the expression below:

       P1 V1 = P2V2

The unknown is P2;

            1 x 0.25  = P2 x 0.22

                 P2  = 1.14atm

7 0
3 years ago
What did scientists discover about the ocean floor after sonar was invented?
adoni [48]
<span>led to the discovery of many new sea floor features of smaller scales. Deep sea trenches and sea volcanoes.
If that helped please mark brainliest! <3

-Procklownyt</span>
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3 years ago
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