Write an equation for the hanger diagram and then us the sketch to show how to solve the equation algebraically.
1 answer:
Step-by-step explanation:
Since there are 3 w's and a 1 on one side and 7 1's on the other and the hanger diagram shows they are even, we can set them equal to each other.
3w + 1 = 7 <em>Subtract</em><em> </em><em>1</em><em> </em><em>from both</em><em> </em><em>sides</em>
3w = 6 <em>Divide</em><em> </em><em>3</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em>
w = 2
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-px + r = - 8x - 2
-px + r + 8x +2 = 0
-px +8x = -r -2
x(8-p) = -r -2
x=
=

Answer:

Explanation:
<u>Given Expression</u>:
Use the Quadratic Formula:

<u>insert coefficients</u>





Answer:
8. 14 for the third question.
9. 18 for the forth question.
Step-by-step explanation:
the third and forth orange equations.
1. 2/3 - (1/4)*(4/9)
2/3-4/36
24/36-4/36
20/36 also same as 4/9 (D)
2. It's B. (-3*(2*7)=(-3*2)*7
3. -4+(-6)*(-3)
-4+18
-14 (b)