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vladimir1956 [14]

3 years ago

6

From ground an electrical worker looks up at an electrical tower with 2 sets of T bars, the lower has a 25° angle of elevation f

rom the ground, and the upper a 40° angle of elevation for the ground. What is the distance between the sets of T bars. Write only the numeric value rounded to the nearest whole.
Helpp me plzzz

1 answer:

jolli1 [7]3 years ago

4 0

Did u get any of the answersss!!?

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In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

2 years ago

Solve the equation and enter the value of x below. x(8 + 9) = 34

vodomira [7]

$\huge\boxed{\mathfrak{Answer}}$

$x(8 + 9) = 34 \\ 8x + 9x = 34 \\ 17x = 34 \\ x = \frac{34}{17} \\ x = 2$

=> The answer is <u>2</u><u>.</u>

5 0

2 years ago

A dinner plate fits tightly into a box whose square base has a perimeter of 28 inches.What is the circumference of the plate?

ZanzabumX [31]

The diameter of the plate would be equal to the length of a side of the box.

Find the length of the box by dividing the perimeter by 4:

28 / 4 = 7 inches.

The diameter is 7 inches.

Circumference is found by multiplying the diameter by pi:

The exact circumference is 7PI

Using 3.14 for pi, the decimal answer is:

3.14 x 7 = 21.98 inches ( round answer as needed.)

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JulsSmile [24]

Answer:18 grams

Step-by-step explanation:

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3 years ago

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uysha [10]

Answer: 56

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