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3 years ago

Plzzzzzzzzzzzzzzzzzzzzzzzzzzz in need help

Mathematics

1 answer:

scoundrel [369]3 years ago

3 0

Answer:

I think it's C but I'm not too sure

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1/5 divided by (6 x 4)

Naily [24]

Answer:

1/120

Step-by-step explanation:

(1/5) / (6 * 4)

First simplify:

(1/5) / 24

Then, multiply be the reciprocal of 24 (Skip, Flip, Multiply):

$\frac{1}{5} (\frac{1}{24})$

and you get:

1 / (5 * 24)

1/120

3 0

2 years ago

Carlos packed 3 jars with olives. each jar weighed 14 ounces. what is the total weight of the 3 jars?

nlexa [21]

Then, the total weight would be: 3 * 14 = 42 Ounces

6 0

3 years ago

Simplify -4(-9p + -3) +2(-2p + 6)

zalisa [80]

Answer:32p+24

Step-by-step explanation:

-4(-9p + -3) +2(-2p + 6)

36p+12-4p+12

32p+24

Hope it helped you

4 0

3 years ago

Evaluate [3+(8-2)]x5

photoshop1234 [79]

Answer:

Step-by-step explanation:

Subtract the numbers

(3+(8-2)). x5

[3+6)]. x5

Add the numbers

[3+6]. x5

[9]. x5

8 0

3 years ago

A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the

creativ13 [48]

Answer:

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

$2r+s=18$

$s=r \theta$

$2r+r \theta=18$

solve for r

$r=\frac{18}{2+\theta}$

step 2

Find the value of s

$s=r \theta$

substitute the value of r

$s=\frac{18}{2+\theta}\theta$

step 3

we know that

The area of complete circle is equal to

$A=\pi r^{2}$

The complete circle subtends a central angle of 2π radians

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

$\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}$

substitute the value of r

$A=\frac{(\frac{18}{2+\theta})^2\theta}{2}$

$A=\frac{162 \theta}{(\theta+2)^2}$

Convert to function notation

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

6 0

3 years ago