Is 1/4 squared a rational?
1 answer:
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The answer is 150 million.
Step 1. Calculate the growth rate.
Step 2. Calculate the population number in 2014.
We will use the formula for exponential growth:
A = P * eⁿˣ
where:
A - the final amount (value)
P - the initial amount (value)
e - the mathematical constant (e ≈ 2.72)
n - the growth rate
x - the time
Step 1:
A = 141 million = 141 000 000
P = 136 million = 136 000 000
n = ?
x = 2000 - 1991 = 9
Therefore:
Logarithm both sides of the equation:
Step 2:
Now when we know the growth rate, it is easy to estimate the population in 2016
A = ?
P = 141 000 000
n = 0.004
t = 2016 - 2000 = 16
Thus, the population will be nearly 150 million in 2016
Step 1. Calculate the growth rate.
Step 2. Calculate the population number in 2014.
We will use the formula for exponential growth:
A = P * eⁿˣ
where:
A - the final amount (value)
P - the initial amount (value)
e - the mathematical constant (e ≈ 2.72)
n - the growth rate
x - the time
Step 1:
A = 141 million = 141 000 000
P = 136 million = 136 000 000
n = ?
x = 2000 - 1991 = 9
Therefore:
Logarithm both sides of the equation:
Step 2:
Now when we know the growth rate, it is easy to estimate the population in 2016
A = ?
P = 141 000 000
n = 0.004
t = 2016 - 2000 = 16
Thus, the population will be nearly 150 million in 2016
Answer:
See image
Step-by-step explanation:
To graph the inequality
-2x + y >= -10
Change it to y = mx + b form, use a solid line (bc of the "or equal to" underline)
y >= 2x - 10 We have y-intercept at -10 and slope 2/1, shading goes above the line.
The other graph is an absolute value graph; it has a v-shape. The 7 makes it stretched 7 times taller (and skinnier) the -4 by the x shifts the whole graph to the right 4 units. The -4 at the end of the equation shifts the whole graph down 4 units. See image. The shading goes above the V (kind of looks like inside)
The solution to the system is where the shading of the two overlap. It is mostly the shading for the absolute value graph except for a tiny triangle at the bottom. See image.
