All categories

3 years ago

CAN SOMEONE PLEASE HELP but also draw the graph with the answer so it will be easier for me to understand plzzz !!!

Mathematics

1 answer:

mestny [16]3 years ago

5 0

Answer:

do week one first then the next. trust me dont get stressed god didnt get everything done in one day either.

Step-by-step explanation:

You might be interested in

A tree is 3 ft tall casts a shadow that is 2 ft long. Find the length of the shadow that a 6 ft tree costs.

Anni [7]

Answer:

4 feet

Step-by-step explanation:

Plz brainliest ,Hope I could Help

6 0

3 years ago

The mean length of 10 childrens' index finger is 12.6cm.

ICE Princess25 [194]

Get total lengths by multiplying:

10 x 12.6 = 126

6 x 16.1 = 96.6

Add the total lengths together and divide by 16:

126 + 96.6 = 222.6

222.6 / 16 = 13.9125

Rounded to 2 decimal places = 13.91

answer: 13.91

5 0

2 years ago

What is 18.75 rounded two decimals places

Serggg [28]

The answer would be 18.8

7 0

3 years ago

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.

seropon [69]

Answer:

$h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}$

Step-by-step explanation:

1) The Fundamental Theorem of Calculus in its first part, shows us a reciprocal relationship between Derivatives and Integration

$g(x)=\int_{a}^{x}f(t)dt \:\:a\leqslant x\leqslant b$

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

$h(x)=\int_{a}^{x^{2}}\sqrt{5+r^{3}}\therefore h'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left (\int_{a}^{x^{2}}\sqrt{5+r^{3}}\right )\\h'(x)=\sqrt{5+r^{3}}\\Chain\:Rule:\\F'(x)=f'(g(x))*g'(x)\\h'=\sqrt{5+r^{3}}\Rightarrow h'(x)=\frac{1}{2}*(r^{3}+5)^{-\frac{1}{2}}*(3r^{2}+0)\Rightarrow h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}$

3) To test it, just integrate:

$\int \frac{3r^{2}}{2\sqrt{r^3+5}}dr=\sqrt{r^{3}+5}+C$

5 0

3 years ago

Hi what is 398÷45.

EleoNora [17]

Answer:

8.84444444444

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers