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Marina86 [1]
4 years ago
7

Geometry math problem

Mathematics
1 answer:
sashaice [31]4 years ago
3 0
Go -6 for x axis and -4 for y axis
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Lin has a drawing with an area of 20 in squared. If she increases all sides by a scale factor of 4, what will the new area be?
diamong [38]

The new area will be 320 in²

<em><u>Explanation</u></em>

Lin has a drawing with an area of 20 in² and she increases all sides by a scale factor of 4.

<u>The general rule</u> we need to use here.......

"<em>If the lengths of the sides in a shape are all increased by a scale  factor of  k, then the area will be increased by a scale factor of  k^2"</em>

Here the sides are increased by a scale factor of 4. So, the area will be increased by a scale factor of  (4)^2 =16

Thus, the new area will be:  (20*16)in^2 = 320in^2

8 0
3 years ago
Screen Shot 2021-05-25 at 9.56.13 AM
lapo4ka [179]

Answer:

where is the question

have a good day :)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A graduated cylinder actually contains 7.5 mm of water 1/2 measures the volume of the water inside the graduated cylinder is mea
Verdich [7]

Answer:

6.667%

Step-by-step explanation:

Given that:

Actual measurement = 7.5 mm

Measured value = 7 mm

Percentage error :

Error / (Actual measurement.) * 100%

(Actual measurement - measured value)

Error = 7.5 - 7 = 0.5 mm

Percentage error = (0.5 / 7.5) * 100%

Percentage error = 0.0666666 * 100%

= 6.667%

7 0
3 years ago
How do you rationalize the numerator in this problem?
maw [93]

To solve this problem, you have to know these two special factorizations:

x^3-y^3=(x-y)(x^2+xy+y^2)\\ x^3+y^3=(x+y)(x^2-xy+y^2)

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:

\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y

That tells us that we have:

\frac{x-y}{h}

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

\frac{x-y}{h}*\frac{x^2+xy+y^2}{x^2+xy+y^2}=\frac{x^3-y^3}{h*(x^2+xy+y^2)}

So, we have:

\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}

That is our rational expression with a rationalized numerator.

Also, you could just mutiply by:

\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}

Either way, our expression is rationalized.

7 0
4 years ago
What is equivalent to negative 2/5
Gala2k [10]

That would be -0.4, my good sir.

8 0
3 years ago
Read 2 more answers
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