Question

What is the volume of the following shape?

Answer 1

Answer:

$V=V_{1}+V_{2}=96+36=132\: cm^{3}$

Step-by-step explanation:

We can divide it into two parts:

First, we can fin the volume of the parallelepiped:

h1 = 16 cm

w1 = 2 cm

d1 = 3 cm

$V_{1}=h_{1}*w_{1}*d_{1}=16*2*3=96\: cm^{3}$

Now, the volume of the second parallelepiped is:

h2 = (8-2) cm = 6 cm

w2 = 2 cm

d2 = 3 cm

$V_{2}=h_{2}*w_{2}*d_{2}=6*2*3=36\: cm^{3}$

Finally, the total volume will be the addition of these two volumes.

$V=V_{1}+V_{2}=96+36=132\: cm^{3}$

I hope it helps you!