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3 years ago

Which of the following grid correctly graphs the points A (3,1) and C (1,3)

Mathematics

2 answers:

love history [14]3 years ago

6 0

The top right in the corner

musickatia [10]3 years ago

4 0

Answer:

its the top right

Step-by-step explanation:

x before y

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Please help 20 points

12345 [234]

Answer:

x =± (√ 317/ 2 )+( 15 /2)

6 0

3 years ago

What is the hypotenuse and how can you tell whether it's a hypotenuse or a short leg? Thx

neonofarm [45]

The hypothenuse is the opposite side of the right angle

so that means that in this triangle the hypotenuse is 7

3 0

3 years ago

Read 2 more answers

Please hurry I will mark you brainliest 8(3 - i) = 5(2 - 2i)

Mrac [35]

Answer:-7

Step-by-step explanation:

24-8i=10-10i

24-10=-10i+8i

14=-2i

I=-7

6 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

Identify the percent of change an increase or decrease then find percent of change one hundredfifty pounds to one hundred thirty

Alex777 [14]

Answer:

−10%change

10%decrease

Step-by-step explanation:

V2−V1)|V1|×100

=(135−150)|150|×100

=−15150×100

=−0.1×100

=−10%change

=10%decrease

Note: Percent Change is NOT the same as Percent Difference between 150 and 135.

Hope this helps!

6 0

3 years ago