Answer:
if it takes 4 people for 2 days
4+4= 8
so it would only take 8 people for 1 day
Answer:
Polynomials are classified according to their number of terms. 4x3 +3y + 3x2 has three terms, -12zy has 1 term, and 15 - x2 has two terms. As already mentioned, a polynomial with 1 term is a monomial. A polynomial with two terms is a binomial, and a polynomial with three terms is a trinomial.
Answer:
1. 7x
2. 8x - 1
3. 6x + 12
4. 3x + 4
5. 13x - 7
Step-by-Step Explanation:
Hope this helps!
Answer:
A) there are 13 cards per suit and 4 suits, a total of 52 cards. So there are 13*2=26 red cards in a deck of 13*4=52, the odds of drawing a red card are 26/52=1/2=50%
B) Again outside knowledge is required, you name four suits but not their colors. Nonetheless, unless this is a very unusual deck, the diamonds and hearts are red, spades and clubs black. So that’s 2 red suits out of 4 suits. 2/4=1/2=50%
C) there are 2 black suits and 2 red suits. The odds of getting a red card are 2/(2+2)=2/4=1/2 or 50%
Each of those answers is a different way to figure the odds, they come out the same each time, as expected.
However, what if we assume that you mean… when drawing a 5 card poker hand? Or when Penn Jillette asks you “is this your card?”+ Or if you draw every card in the deck? Or if you are playing some macabre game in which you die if you draw the ace of spades but you may only stop drawing if you draw a red card?
There are myriad possible meanings to your question, I’ve just made the simplest assumption and given the odds on that… but my answer is woefully incomplete.
+ Hint, when Penn Jillette asks you “is this your card” your card is always the 3 of clubs. So… 0% chance.
So assuming the underlined decimal is the second 8, let's answer the question.
Hundreds: 0 | Tens: 8 | ones: 3 | . | tenths: 5 | hundredths: 8 | thousandths: 5 | 10 thousandths: 1
So since the second 8 is in the hundredths place, we know it's either B or C.
When we round for 5, we always round up, so the answer would be 83.59
So the answer is B.
Hope this helped! If you have any more questions or don't understand please comment or DM me. :)
