Answer:
Step-by-step explanation:
The problem is:
<em>Lola says: Argos, my dog, has 10 kilograms less than Roco. How much kilograms Argos has?</em>
<em />
This problem is about algebraic language. We just need to express the ordinaty language into an equation.
We know the words less means difference. So, let's call 
Argos' weight and 
Roco's weight. We can expresse the given problem as
Notice that we applied a difference due to the word "less" in the problem.
Therefore, Argo's weight is given by the expression
Answer:
x=12
Step-by-step explanation:
16x-30-(14x-6)=2x-24=0. add 24 on both sides to get 2x=24. divide by 2 on both sides to get x=12
Dy/dx = (ycos(x))/(1 + y²)
(1 + y²)/y dy = cos(x) dx
(1/y + y) dy = cos(x) dx
Integrating:
ln(y) + y²/2 = sin(x) + c
ln(1) + 1/2 = sin(0) + c
c = 1/2
Thus,
ln(y) + y²/2 = sin(x) + 1/2
Answer:
x = 5/-8
Step-by-step explanation:
4x = 12x + 5
4x - 12x = 5
-8x = 5
x = 5/-8
Answer: 16 in
Explanation:
PQ/QR = PT/TS
PQ/4 = 12/3
PQ x 3 = 12 x 4 (cross multiply)
PQ x 3 = 48
PQ = 48/3
PQ = 16
