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hoa [83]
3 years ago
7

AB + energy→ A +B

Chemistry
1 answer:
ICE Princess25 [194]3 years ago
6 0

Answer:

b. endothermic decomposition

Explanation:

Decomposition reaction:

It is the reaction in which one reactant is break down into two or more product.

AB → A + B

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

A + B      →      AB

Endothermic reactions:

The type of reactions in which energy is absorbed are called endothermic reactions.

In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.

For example:

C +  H₂O  + 131 kj/mol  →  CO  + H₂

Thus, in given reaction energy is added and AB compound is decomposed to give A and B so this reaction is endothermic decomposition.

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The element californium (cf) sells for $1000 per µg. assuming 6.02 x 1023 atoms of cf have a mass of 251 grams, how many atoms o
saveliy_v [14]

Answer:- 2.40*10^1^0atoms

Solution:- It is a simple unit conversion problem. We could solve this using dimensional analysis.

We know that, 1 US dollar = 100 cents

1 cent  = 1 US penny

So, 1 US dollar = 100 US pennies

1g=10^6\mu g

Let's make the set up starting with 1 penny as:

1penny(\frac{$1}{100pennies})(\frac{1\mu g}{$1000})(\frac{1g}{10^6\mu g})(\frac{6.02*10^2^3atoms}{251g})

= 2.40*10^1^0atoms

Therefore, we can bye 2.40*10^1^0atoms of Cf in one US penny.

3 0
3 years ago
What would the molecule CH₄ be classified as?
larisa [96]

Answer:

Alkane

Explanation:

Definition of Alkane "any of the series of saturated hydrocarbons including methane, ethane, propane, and higher members. (google dictionary)"

CH4 is methane.

6 0
4 years ago
Use the periodic table to determine the electron configuration for iodine (i). express your answer in condensed form.
Dovator [93]
Iodine electron configuration is:

1S^2 2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 5S^2 4d^10  5P^5
when Krypton is the noble gas in the row above iodine in the periodic table,
we can change 1S^2  2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 by the symbol
[Kr] of Krypton.

So we can write the electron configuration of Iodine:
[Kr] 5S^2 4d^10 5P^5

8 0
3 years ago
Read 2 more answers
HNO3 + H2SO4 + NO
77julia77 [94]

Explanation:

The two half equations are;

3e + HNO3 → NO

S→ H2SO4 + 6e

When balancing half equations, we have to make sure the number of electrons gained is equal to the number of electrons lost.

<em>Which factor will you use for the top equation?</em>

We multiply by 2 to make the number of electrons =  6e

<em>Which factor will you use for the bottom equation?</em>

We multiply by 1 to make the number of electrons = 6e

3 0
3 years ago
What is true of a substance with a lot of mass?
fomenos

Answer:

A. it contains a lot of matter

5 0
3 years ago
Read 2 more answers
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