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3 years ago

I don't understand this can anyone help please.

Mathematics

1 answer:

dsp733 years ago

8 0

Answer:

Radius is 9 cm

Diameter is 18 cm

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I’m sure this is easy but I hateeee geometry. help ASAP plsssss

hram777 [196]

Given points

(-4,3)
(2,5)

Distance:-

$\\ \sf\longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\\ \sf\longmapsto \sqrt{(2+4)^2+(5-3)^2}$

$\\ \sf\longmapsto \sqrt{(6)^2+(2)^2}$

$\\ \sf\longmapsto \sqrt{36+4}$

$\\ \sf\longmapsto \sqrt{40}$

$\\ \sf\longmapsto 6.2$

8 0

3 years ago

Juan sells 2 sizes of dried wreaths it takes him 3 hours to make each large and 2 hours to make each small one. he has material

Karo-lina-s [1.5K]

Answer: The answer is (2,9) and (6,3).

Step-by-step explanation: Given that Juan sells 2 sizes of dried wreaths. He takes 3 hours to make each large one and tales 2 hours to make each small one. Also, he has material for maximum 6 large wreaths or maximum 9 small wreaths.

Let, 'x' and 'y' be the number of number of large wreaths and number of small wreaths respectively made by Juan.

So, according to the given information, we have the following relations -

$3x+2y\leq 24,~~x\leq 6,~~y\leq 9.$

We tried plotting these inequalities in the graph paper (please see the attached figure), and found that the following two solutions will fit the situation perfectly.

Point A (x = 2, y = 9) and point B (x = 6, y = 3).

Thus, the two possible combinations are

(i) 2 large wreaths and 9 small wreaths, and

(ii) 6 large wreaths and 3 small wreaths.

7 0

3 years ago

Solve the differential equation by variation of parameters.<br><br> y''+y=secx

suter [353]

Answer:y=

Acosx+Bsinx +cosx ln(cosx)+x sinx

Step-by-step explanation:

given equation y''+y=secx

auxiliary equation

$p^2+1=0\\p=\pm i$

so CF is y=Acosx+Bsinx

now

$y_1(x)=cosx \ \ \ \ y_2(x)=sinx\\{y_1}'(x)=-sinx \ \ \ \ {y_2}'(x)=cosx$

using wronskian formula

$W=\begin{vmatrix}cosx &sinx \\ -sinx & cosx\end{vmatrix}$

= $cos^2x+sin^2x=1$

now f(x)=secx

$u=-\int \frac{f(x)y_2(x)}{W(x)}dx \ and \ v=\int \frac{f(x)y_1(x)}{W(x)}dx$

$u=-\int \frac{secx\times sinx}{1}dx \ and \ v=\int \frac{secx\times cosx}{1}dx$

$u=-\int tanx dx \ and \ v=\int {1}dx$

$u=ln(cosx) \ \ \ and \ \ v=x$

now particular integrals are

PI=cosx ln(cosx)+x sinx

total solution

y= C.F+P.I

y=Acosx+Bsinx +cosx ln(cosx)+x sinx

8 0

3 years ago

Log10^x - log10^3 - 1

Pavel [41]

Answer:

1^x-2

Step-by-step explanation:

First you put log(10)^x into the calculator, the product is 1^x. Then you subtract that by log(10)^3 which you you get 1^x-1 then you subtract that answer by 1 to get 1^x-2.

8 0

3 years ago

Tasha spent 55 hours in 2 weeks working on a science project. She worked 32 hours the first week. Write and solve an addition eq

blondinia [14]

Answer:

55 = 32 + x

55-32 = x

x =23

3 0

3 years ago