Y=29-2(1)
y=29-2=27
(1,27)
y=29-2(3)
y=29-6=23
(3,23)
y=29-2(4)
y=29-8=21
(4,21)
y=29-2(5)
y=29-10=19
(5,19)
I'm guessing Q lol. I hope that's helpful.
If you do not mind me asking, what did Seth write? Us helpers cannot answer it if we do not have the full question. I apologize if this seems rude.
If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answer:
you can name it a or b like any letters
